Question

Find the area of a triangle formed by placing the vectors [3, 6] and [7, 1] tail-to-tail.

Answer 1

Answer:

a. $A=10u^{2}$

b. View graph

c. 6.40u

Step-by-step explanation:

knowing that the triangle area is equal to base by heigh between two, then:

$A=\frac{bh}{2}=\frac{5*4}{2}=10u^{2}$

The length of the longest altitude of your triangle is:

$c^{2}=a^{2}+b^{2}=5^{2}+4^{2}=25+16=41\\ c=\sqrt{41}=6.40u$

finally it can be seen that the position of the triangle does not matter, as long as the base and heigh are maintained, the area of ​​the triangle will be the same