Find the area of a triangle formed by placing the vectors [3, 6] and [7, 1] tail-to-tail.

Mathematics

1 answer:

Usimov [2.4K]3 years ago

6 0

Answer:

a. $A=10u^{2}$

b. View graph

c. 6.40u

Step-by-step explanation:

knowing that the triangle area is equal to base by heigh between two, then:

$A=\frac{bh}{2}=\frac{5*4}{2}=10u^{2}$

The length of the longest altitude of your triangle is:

$c^{2}=a^{2}+b^{2}=5^{2}+4^{2}=25+16=41\\ c=\sqrt{41}=6.40u$

finally it can be seen that the position of the triangle does not matter, as long as the base and heigh are maintained, the area of the triangle will be the same

You might be interested in

55. (a) If alpha and beta are the roots of the equation xsquare+ px+q=0 and beta>alpha find the square of the

densk [106]

Answer:

√(p²-4q)

Step-by-step explanation:

Using the Quadratic Formula, we can say that

x = ( -p ± √(p²-4(1)(q))) / 2(1) with the 1 representing the coefficient of x². Simplifying, we get

x = ( -p ± √(p²-4q)) / 2

The roots of the function are therefore at

x = ( -p + √(p²-4q)) / 2 and x = ( -p - √(p²-4q)) / 2. The difference of the roots is thus

( -p + √(p²-4q)) / 2 - ( ( -p - √(p²-4q)) / 2)

= 0 + 2 √(p²-4q)/2

= √(p²-4q)

7 0

2 years ago

P(t) = 250 * (3.04)^t/1.98,

Alex17521 [72]

Answer:

The concept which best describes the change of the population is the derivative of $p(t)=250(3.04)^{\frac{t}{1.98}}$ .

Step-by-step explanation:

Observe that the function $p(t)=250(3.04)^{\frac{t}{1.98}}$ describes the amount of rabbits at the time t (in years) but no the rate of change of the population at a given instant. So you have to use the derivative of $p(t)$ to obtain that rate of change at any instant. For example, if we derivate the function $p(t)=250(3.04)^{\frac{t}{1.98}}$ we obtain: