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guajiro [1.7K]
3 years ago
6

What is the density if the weight is 40.5 and the volume is 15.0

Chemistry
1 answer:
Stolb23 [73]3 years ago
5 0
This is what my teacher did (example). So if the weight was 40.5 and the volume was 15.0:
<span>
d = 40.5 g / 15.0 mL  (that means you divide it)d = 2.70 g/mL
</span>

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How to do dots and cross diagrams
Likurg_2 [28]

Answer:

Draw circles to represent the electron shell of each atom overlapping the circles where the atoms are bonded. Add dots to represent the outer electrons of one type of atom (H). Add crosses to represent the outer electrons of the other type of atom (Cl). Make sure the electrons are always in pairs.

6 0
3 years ago
imagine you have four food dyes to test A, B, C and D imagine that you are going to investigate which food dye diffuses more qui
Lady_Fox [76]

Answer:

You will change which food dye is used. You will measure how quickly the dyes diffuse. You could use a timer to see how long the dye takes to completely diffuse.

5 0
3 years ago
Applying the rules of significant figures, which of the following would be the correct value for the density of a substance whic
lilavasa [31]

16 g/ml

<h3>Further explanation</h3>

Given

mass = 32.40 g

volume = 2.0mL

Required

Density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Input the value :

ρ = 32.40 g / 2.0 ml

ρ = 16.2 g/ml

Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.

32.40 = 4 sig.fig

2.0 = 2 sig fig

The answer must be 2 sig fig

So the answer = 16 g/ml

6 0
3 years ago
If a student has 50.0 mL of a solution of 0.100 M HCI, how could they make a solution with a concentration of 0.0500 M?
vfiekz [6]

Answer:

100 ml

Explanation:

c1×v1=c2×v2

50(0.100)=0.0500(v2)

5=0.0500(v2)

5/0.0500=0.0500/0.0500(v2)

100= v2

5 0
3 years ago
.The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temper
Elis [28]

Explanation:

It is given that the initial mass of benznene is 7.9286 g

Mass of benzene left = 5.9987 g

So, mass of benzene with which gas get saturated will be calculated as follows.

               = 7.9286 g  - 5.9987 g  = 1.9299 g

Therefore, moles of benzene with which gas get saturated = \frac{mass}{ molar mass}

                = \frac{1.9299 g}{78.112 g/mol}

                = 0.0247 moles

Temperature = 27.3^{o}C = 27.3 + 273.15 = 300.45 K

Volume = 5.01 L

So, according to ideal gas equation PV = nRT

Putting the given values into the ideal gas equation as follows.

                       PV = nRT

           P \times 5.01 L = 0.0247 mol \times 62.36 torr-liter/mol K \times 300.45 K

                   P = \frac{462.781 torr-liter}{5.01 L}

                      = 92.371 torr

Hence, we can conclude that vapor pressure of benzene is 92.371 torr.

8 0
3 years ago
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