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Vinvika [58]
3 years ago
14

Applying the rules of significant figures, which of the following would be the correct value for the density of a substance whic

h has a mass if 32.40 g and a volume of 2.0mL?
16.20 g/mL
16 g/mL
0.06 g/mL
5.00 g/mL​
Chemistry
1 answer:
lilavasa [31]3 years ago
6 0

16 g/ml

<h3>Further explanation</h3>

Given

mass = 32.40 g

volume = 2.0mL

Required

Density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

Input the value :

ρ = 32.40 g / 2.0 ml

ρ = 16.2 g/ml

Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.

32.40 = 4 sig.fig

2.0 = 2 sig fig

The answer must be 2 sig fig

So the answer = 16 g/ml

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Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
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The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

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K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

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CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

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[1] +  [2] + [3]

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 ( on adding the equilibrium constant will get multiplied with each other)

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K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

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