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sweet [91]
3 years ago
14

What must be balanced in order to have a balanced chemical equation?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
5 0
Both sides need to be balanced?
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What is the importance of standardization in chemistry​
Anika [276]

Answer:

Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results

5 0
3 years ago
On the basis of the information above, a buffer with a pH = 9 can best be made by using
telo118 [61]

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for \mathbf{H_3PO_4 , H_2PO^{-}_4 ,  HPO_4^{2-}} are \mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \  5\times 10^{-13}} respectively.

\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}

\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}

\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}

The reason while option D is the best answer is that, the value of pKa for both

\mathbf{H_2PO^{-}_4 ,\  \& \  HPO_4^{2-}} lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}

3 0
3 years ago
What can be formed by atoms of same element (H) or atoms of different 20 points<br> elements (CO)? *
NARA [144]

Answer:

Molecules

Explanation:

If you had more than one atom chemically bonded together, then regardless of the types of atoms that are bonded, you're going to have a molecule regardless.

4 0
3 years ago
How do whales, bats, and dolphins use echolocation?
Nataly [62]
I feel like all of them are true


8 0
3 years ago
Read 2 more answers
Enter your answer in the provided box. On a certain winter day in Utah, the average atmospheric pressure is 718 torr. What is th
AnnZ [28]

Answer:

The correct answer is 0.047 mol/L

Explanation:

The atmospheric air is a mixture of gases. We can assume an ideal behavior of the gas and use the ideal gas equation:

PV= nRT

where P is the pressure, V is the volume, n is the number of moles, R is a constant (0.082 L.atm/K.mol) and T is the temperature in K.

We have to first convert the pressure from Torr to atm:

760 Torr= 1 atm

⇒ 718 Torr x 1 atm/760 Torr = 0.945 atm

Then, we convert the temperature from ºC to K:

0ºC = 273 K

⇒ -29ºC+273= 244 K

Finally, we introduce the data in the equation and calculate de densitiy, which is the moles per liters of gas (n/V):

PV = nRT

n/V= P/RT

n/V = (0.945 atm)/(0.082 L.atm/K.mol x 244 K) = 0.047 mol/L

7 0
3 years ago
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