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zhuklara [117]
3 years ago
6

The carbon atom in co2 shares _______blank electron pairs. after the reaction with h2o to form h2co3 is completed, the carbon at

om shares ________blank electron pairs. question 4 choices choice
a., two; two choice
b., four; four choice
c., two; three choice
d., three; two

Chemistry
2 answers:
lisov135 [29]3 years ago
4 0
B , four , four ........

olya-2409 [2.1K]3 years ago
3 0

Answer:

b., four; four

Explanation:

As an element, carbon is tetravalent, it has 4 outer shell electrons and oxygen has 6 outer shell electrons. The carbon dioxide molecule is formed from one carbon atom and two oxygen atoms by two double covalent bonds. In making CO₂, two electrons of carbon share with each oxygen atoms resulting in 4 bonding electrons in total. Carbon dioxide's strong double bonds make it very stable.

In reaction with water, carbon forms double covalent bond with one of the oxygen of CO₂ and with two single covalent bonds one with other oxygen atoms of CO₂ and one with the oxygen atom of H₂O forming carbonic acid (H₂CO₃). Thus, carbon shares 4 electrons.  

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6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
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Given: V_{1} = 0.20 mL,         T_{1} = 27^{o}C

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\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

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5 0
3 years ago
Water at the bottom of a narrow metal tube is held at a constant temperature of 293 K. The total pressure of air (assumed dry) i
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3 years ago
A student uses 0. 0821 LĂ˘â‚¬Ë atm/mol Ă˘â‚¬Ë K as the value of the gas constant. What is most likely true about the variables i
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The variables in the ideal gas constant has V as the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

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The given value of R has been 0.0821 L.atm/mol.K

The unit in gas constant has been L (Liter) for volume (V).

The unit of pressure (P) has been atm.

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Thus the gas law constant used by student has V has the unit of liters and T has the unit of Kelvin. Thus, option C is correct.

For more information about the gas constant, refer to the link:

brainly.com/question/24814070

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