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Answer:
Mass of carbon = 109.1 g
Explanation:
Given data:
Mass of carbondioxide = 400 g
Mass of carbon = ?
Solution:
Molar mass of carbon = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Mass of carbon in 400g of CO₂:
Mass of carbon = 12 g/mol/44 g/mol × 400 g
Mass of carbon = 109.1 g
Answer:
Wurzite has a higher Madelung constant when compared with Sphalerite therefore Wurizite is more stable.
Explanation:
Zinc Sulphide is a chemical compound that exhibits polymorphism. This means Zinc Sulphide can exists in different forms as a compound. Zinc Sulphide has two common polymorphs named; Wurtzite and Sphalerite .
This two polymorphs are crystalline in structure. Wurtzite is hexagonal in shape while Sphalerite is cubic in shape.
Madelung constant was named after German Physicist Erwin Madelung. Madelung constant is dependent on the the way ions are arranged in a solid substance or molecule. It is used to calculate the amount of energy required to move an ion from one point to the another in a crystal substance.
Madelung constant for Wurtzite is 1.64132 and for Sphalerite is 1.63806. Due to the fact that Wurtzite has a slightly higher Madelung constant that Sphalerite, it tends to be more stable than Sphalerite.
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Answer:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
2.6592 grams of oxygen remain in the flask.
Explanation:
Volume of the flask remains constant = V = 2.0 L
Initial pressure of the oxygen gas = 
Initial temperature of the oxygen gas = 
Final pressure of the oxygen gas = 
Final temperature of the oxygen gas = 
Using Gay Lussac's law:


1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
Moles of oxygen gas = n
(ideal gas equation)

Mass of 0.08310 moles of oxygen gas:
0.08310 mol × 32 g/mol = 2.6592 g
2.6592 grams of oxygen remain in the flask.
Answer:
New volume V2 = 2.565 L
Explanation:
Given:
Old volume V1 = 10.8 L
Old pressure P1 = 0.38 atm
New presuure P2 = 1.6 atm
Find:
New volume V2
Computation:
P1V1 = P2V2
So,
10.8 x 0.38 = V2 x 1.6
New volume V2 = 2.565 L