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zhuklara [117]
3 years ago
6

The carbon atom in co2 shares _______blank electron pairs. after the reaction with h2o to form h2co3 is completed, the carbon at

om shares ________blank electron pairs. question 4 choices choice
a., two; two choice
b., four; four choice
c., two; three choice
d., three; two

Chemistry
2 answers:
lisov135 [29]3 years ago
4 0
B , four , four ........

olya-2409 [2.1K]3 years ago
3 0

Answer:

b., four; four

Explanation:

As an element, carbon is tetravalent, it has 4 outer shell electrons and oxygen has 6 outer shell electrons. The carbon dioxide molecule is formed from one carbon atom and two oxygen atoms by two double covalent bonds. In making CO₂, two electrons of carbon share with each oxygen atoms resulting in 4 bonding electrons in total. Carbon dioxide's strong double bonds make it very stable.

In reaction with water, carbon forms double covalent bond with one of the oxygen of CO₂ and with two single covalent bonds one with other oxygen atoms of CO₂ and one with the oxygen atom of H₂O forming carbonic acid (H₂CO₃). Thus, carbon shares 4 electrons.  

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Oxygen gas can be prepared by heating potassium chlorate according to the following equation:2KClO3(s)Arrow.gif2KCl(s) + 3O2(g)T
Eduardwww [97]

Answer:

Moles of potassium chlorate reacted = 0.2529 moles

The amount of oxygen gas collected will be 12.8675 g

Explanation:

(a)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 748 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (748 - 17.5) mmHg = 730.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 730.5 mmHg  

V = Volume of the gas = 9.49 L

T = Temperature of the gas = 20^oC=[20+273]K=293K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

730.5mmHg\times 9.49L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{730.5\times 9.49}{62.3637\times 293}=0.3794mol

According to the reaction shown below as:-

2KClO_3(s)\rightarrow 2KCl(s) +3O_2(g)

3 moles of oxygen gas are produced when 2 moles of potassium chlorate undergoes reaction.

So,

0.3794 mol of oxygen gas are produced when \frac{2}{3}\times 0.3794 moles of potassium chlorate undergoes reaction.

<u>Moles of potassium chlorate reacted = 0.2529 moles</u>

(b)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 753 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (753 - 17.5) mmHg = 735.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 735.5 mmHg  

V = Volume of the gas = 9.99 L

T = Temperature of the gas = 20^oC=[20+273]K=293K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

735.5mmHg\times 9.99L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{735.5\times 9.99}{62.3637\times 293}=0.40211mol

Moles of Oxygen gas = 0.40211 moles

Molar mass of Oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.037mol=\frac{\text{Mass of Oxygen gas}}{2g/mol}\\\\\text{Mass of Oxygen gas}=(0.40211mol\times 32g/mol)=12.8675g

<u>Hence, the amount of oxygen gas collected will be 12.8675 g</u>

5 0
3 years ago
Which of the following has a mass of 10.0 g?
Serjik [45]

Answer:

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Explanation:

To solve this problem, we must understand that;

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                        He = 4g/mol

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C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

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What are some ways that organelles are similar to organ system?
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Explanation:

Like organs in an organism, each organelle has a specific function in a cell. All of the organelles work together to carry out the functions of the cell as a whole, just as organs do to an organism. For example, mitochondria are the sites of cellular respiration; they provide energy the cell

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3 years ago
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