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zhuklara [117]
3 years ago
6

The carbon atom in co2 shares _______blank electron pairs. after the reaction with h2o to form h2co3 is completed, the carbon at

om shares ________blank electron pairs. question 4 choices choice
a., two; two choice
b., four; four choice
c., two; three choice
d., three; two

Chemistry
2 answers:
lisov135 [29]3 years ago
4 0
B , four , four ........

olya-2409 [2.1K]3 years ago
3 0

Answer:

b., four; four

Explanation:

As an element, carbon is tetravalent, it has 4 outer shell electrons and oxygen has 6 outer shell electrons. The carbon dioxide molecule is formed from one carbon atom and two oxygen atoms by two double covalent bonds. In making CO₂, two electrons of carbon share with each oxygen atoms resulting in 4 bonding electrons in total. Carbon dioxide's strong double bonds make it very stable.

In reaction with water, carbon forms double covalent bond with one of the oxygen of CO₂ and with two single covalent bonds one with other oxygen atoms of CO₂ and one with the oxygen atom of H₂O forming carbonic acid (H₂CO₃). Thus, carbon shares 4 electrons.  

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Mass of sodium thiosulfate Na_{2}S_{2}O_{3} is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}} = 0.696 molNa_{2}S_{2}O_{3}

Converting the volume of solution to L:

350. mL * \frac{1 L}{1000 mL} = 0.350 L

Finding out the concentration of solution in molarity:

\frac{0.696 mol}{0.350 L} =  1.99 mol/L

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3 years ago
What is the correct name for the compound CaSO4•2H2O?
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5 0
3 years ago
Draw the major product for the reaction of 1-butyne with water in the presence of catalytic TfOH (i.e., CF3SO3H). Then answer th
Mademuasel [1]

Answer:

2-Butanone

Explanation:

From the given information:

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Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

Let us express it as

SO_{\frac{m_{S} }{m_{O} }} = 2

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\   \frac{m_{S} }{m_{O} }= 1

Let us express it as

SO_2_{\frac{m_{S} }{m_{O} }}= 1

Now, for the ratio of both the above-calculated ratios,

\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}

The required ratio is 2:1

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Alex_Xolod [135]
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