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lyudmila [28]
3 years ago
5

If y varies directly as x, and y is 6 when x is 72, which is the value of y when x is 8 ?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

\frac{y}{x} = k

\frac{6}{72} = k

\frac{1}{12} = k

********************************

\frac{y}{x} = k

\frac{y}{8} = \frac{1}{12}

   12y = 8

      y = \frac{8}{12}

      y = \frac{2}{3}

Dmitry_Shevchenko [17]3 years ago
6 0

y = \frac{2}{3}

given y ∝ x

To convert to an equation multiply by k the constant of variation

y = kx

to find k use the given condition y = 6 when x = 72

y = kx ⇒ k = \frac{y}{x} = \frac{6}{72} = \frac{1}{12}

equation is → y = \frac{1}{12} x

when x = 8 then

y = \frac{1}{12} × 8 = \frac{8}{12} = \frac{2}{3}



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