A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .

Mathematics

1 answer:

insens350 [35]2 years ago

6 0

<h2>Answer:0.2352 $m$ </h2>

Step-by-step explanation:

Let the mass of the person be $m$ .

Let the spring constant be $k$ .

Let the displacement in spring be $x$

Let the acceleration due to gravity be $g$

As it is given that the person just stands,the forces are balanced.

So, $mg=kx$

Given,

$m=60Kg\\k=2500Nm^{-1}\\g=9.8ms^{-2}$

$60\times 9.8=2500\times x\\x=\frac{588}{2500}=0.2352m$

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