Question

A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .

Answer 1

Answer:0.2352$m$

Step-by-step explanation:

Let the mass of the person be $m$.

Let the spring constant be $k$.

Let the displacement in spring be $x$

Let the acceleration due to gravity be $g$

As it is given that the person just stands,the forces are balanced.

So,$mg=kx$

Given,

$m=60Kg\\k=2500Nm^{-1}\\g=9.8ms^{-2}$

$60\times 9.8=2500\times x\\x=\frac{588}{2500}=0.2352m$