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When mercurous nitrate paper is exposed to ammonia gas then black color is produced due to the formation of Hg₂NH₂NO₃ + Hg.
The reaction of mercurous nitrate paper with ammonia gas produces the compound mercury amidonitrate and mercury metal.
This mercury amidonitrate contains the mercury I ion (Hg2^+). Since the compound contains mercury I ion, mercury amidonitrate has the formula; Hg₂NH₂NO₃.
The compounds formed therefore are; Hg₂NH₂NO₃ + Hg
Learn more: brainly.com/question/13261915
Answer:
a) Li2CO3
b) NaCLO4
c) Ba(OH)2
d) (NH4)2CO3
e) H2SO4
f) Ca(CH3COO)2
g) Mg3(PO4)2
f) Na2SO3
Explanation:
a) 2Li + CO3 ↔ Li2CO3
b) NaOH * HCLO4 ↔ NaCLO4 + H2O
c) Ba + 2H2O ↔ Ba(OH)2 +
d) 2NH4 + H2CO3 ↔ (NH4)2CO3 + H2O
c) SO2 + NO2 +H2O ↔ H2SO4 + NOx
f) 2CH3COOH + CaO ↔ Ca(CH3COOH)2 + H2O
g) 3MgO + 2H3PO4 ↔ Mg3(PO4)2 + H2O
h) NaOH + H2SO3 ↔ Na2SO3 + H2O
Explanation:
₁₄Si 1s²2s²2p⁶3s²3p².
Principal quantum number (n=3) have four electrons (3s²3p²).
2) ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.
Azimuthal quantum number (l=o) have seven electrons (1s²2s²3s²4s¹).
3) ₈₀Hg [Xe] 4f¹⁴5d¹⁰6s².
Principal quantum number (n=4) have thirty-two electrons (4s²4p⁶4d¹⁰4f¹⁴).
The principal quantum number is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.
Answer: nucleus
Explanation: the bigger the nucleus there more reactive the atom is