Question

Calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​

Answer 1

Moles of benzene

• 70/90=7/9=0.8mol

moles of CCl_4

• 30/154
• 0.2mol

Now

$\\ \rm\Rrightarrow \chi_{C_6H_6}$

$\\ \rm\Rrightarrow \dfrac{\chi_{C_6H_6}}{\chi_{sol^n}}$

$\\ \rm\Rrightarrow \dfrac{0.8}{0.8+0.2}$

$\\ \rm\Rrightarrow \dfrac{0.8}{1}$

$\\ \rm\Rrightarrow 0.8$