The heat required to vaporize 43.9 g of acetone at its boiling point is calculated as below
the heat of vaporization of acetone at its boiling point is 29.1 kj/mole
find the moles of acetone = mass/molar mass
= 43.9g /58 g/mol =0.757 moles
heat (Q) = moles x heat of vaporization
= 29.1 kj/mole x 0.757 moles = 22.03 kj
Answer:

Explanation:
Hello,
In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

Besr regards.
Answer:
4 weeks
Explanation:
It takes 4 weeks for the cyclle to be happening again
Answer:
helium hydrogen
Explanation:
lithium beryllium bottom carbon
The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the following Charle's law equation:
V1/T1 = V2/T2
Where;
- T1 = initial temperature
- T2 = final temperature
- V1 = initial volume
- V2 = final volume
- V1 = 9L
- V2 = ?
- T1 = 325K
- T2 = 450K
9/325 = V2/450
325V2 = 4050
V2 = 4050/325
V2 = 12.46L
Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
Learn more about volume at: brainly.com/question/2817451