Answer B: The graph crosses the y-axis at (0,5), increasing form x=-10 to x=2 and remaining constant from x=2 to x=10.
You only need one of them:
(135 mile²) x (5,280 feet/mile)²
= (135 mile²) x (27,878,400 feet²/mile²)
= (135 x 27,878,400) mile² - feet² / mile²
= 3,763,584,000 feet²
If you convert 7 1/11 to decimals it comes out to .09 there fore 5.89+7.09
Answer: 12.98
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
It's true
if the consecutive angles of a quadrilateral are supplementary it will be parallelogram. like square and rectangular
