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Gala2k [10]
3 years ago
9

Write the first five terms of the geometric sequence in which a1 = 27 and the common ratio is 4/3

Mathematics
1 answer:
tangare [24]3 years ago
5 0

Answer:

c) 27, 36, 48, 64, 256/3

Step-by-step explanation:

We are given a geometric sequence with;

  • First term, a = 27
  • Common ratio, r = 4/3

We are supposed to write the sequence;

We know that a given term in a GP is given by;

T_n=ar^n^-^1, where a is the first term, n is the nth term

Therefore;

First term, a = 27 \\Second term = ar^1= 27(4/3) = 36\\Third term = ar^2=27(4/3)^2=48\\Fourth term =ar^3=27(4/3)^3=64\\Fifth term = ar^4 = 27(4/3)^4 =\frac{256}{3} \\And so forth

Therefore;

The geometric sequence is;

27,36,48,64,\frac{256}{3}

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