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NNADVOKAT [17]
4 years ago
11

A thrill ride at an amusement park travels 55 miles per hour. To the nearest hundredth, how many feet per second is this?

Mathematics
1 answer:
baherus [9]4 years ago
3 0
The first thing you should know are the following conversions:
 1mi = 5280 feet
 1h = 3600 s
 Applying the conversions we have
 (55) (miles / hour) (1/3600) (h / s) (5280/1) (feet / mi) = 80.67feet / s
 answer
 this is 80.67feet / s
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Identifying and Graphing Sequences: lesson 4-1
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Answer:

1) Domain: {   1,2,3,4,5,6}

Range: {12,24,36,48,60,72}

2) First four terms are: 2,5,8,11

3) First four terms are: 8,13,20,29

4) First four terms are: 0,0,2,6

5) First four terms are: 0,1,1.41,1.73

Step-by-step explanation:

1.

n       1      2     3     4      5      6

f(n)    12    24    36   48    60    72

Domain: {   1,2,3,4,5,6}

Range: {12,24,36,48,60,72}

Write first four terms of each sequence

2) f(n)=3n-1

Put n = 1, 3(1)-1 = 3-1 = 2

Put n = 2, 3(2)-1 = 6-1 = 5

Put n = 3, 3(3)-1 = 9-1 = 8

Put n = 4, 3(4)-1 = 12-1 = 11

So, First four terms are: 2,5,8,11

3) f(n)=n^2+2n+5

Put n = 1, (1)^2+2(1)+5= 1+2+5 = 8

Put n = 2, (2)^2+2(2)+5 = 4+4+5= 13

Put n = 3, (3)^2+2(3)+5 = 9+6+5 = 20

Put n = 4, (4)^2+2(4)+5 = 16+8+5 = 29

So, First four terms are: 8,13,20,29

4) f(n)=(n-1)(n-2)

Put n = 1, (1-1)(1-2) = 0(-1) = 0

Put n = 2, (2-1)(2-2) = 1(0) = 0

Put n = 3, (3-1)(3-2) = 2(1) = 2

Put n = 4, (4-1)(4-2) = 3(2) = 6

So, First four terms are: 0,0,2,6

5) f(n) = \sqrt{n-1}

Put n=1 \sqrt{1-1}=\sqrt{0}=0

Put n=2 \sqrt{2-1}=\sqrt{1}=1

Put n=3 \sqrt{3-1}=\sqrt{2}= 1.41

Put n=4 \sqrt{4-1}=\sqrt{3}=1.73

So, First four terms are: 0,1,1.41,1.73

8 0
3 years ago
EAB and DCB are two right triangles. The figure has BED≅ BDE. Point B is the midpoint of segment AC. Prove: EAB≅ DCB
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See the attached picture. 

<span>you are given that ABCE is an isosceles trapezoid. </span>

<span>you are given that AB is parallel to EC. </span>

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<span>you are given that AE and AD are congruent. </span>

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<span>this means that angle 1 is equal to angle 3. </span>

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<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>

<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>

<span>they are either postulates or theorems that have been previously proven. </span>

<span>if not, then you need to go a little deeper and prove some of the statements that you used.. </span>

here's my diagram. 

 

<span>this is not a formal proof, but should give you some ideas about how to proceed. </span>

<span>you can also prove that angle 4 is equal to angle 2 because they are alternate interior angles of parallel lines. </span>

<span>you can also prove that angle 6 is equal to angle 5 because they are alternate interior angles of parallel lines. </span>
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