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Anettt [7]
3 years ago
12

Alyssa spent half of her allowance going to the movies. She washed the family

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

Alyssa's weekly allowance is $20!

Step-by-step explanation:

Read the problem and set up the following equation using X as Alyssa's weekly allowance:

X/2+7=17

1) Subtract 7 from both sides:

X/2=10

2) Multiply both sides by 2:

X=20

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adell [148]
I think that it is 2.4.
8 0
3 years ago
The number of entrees purchased in a single order at a Noodles & Company restaurant has had an historical average of 1.7 ent
SOVA2 [1]

Answer:

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

p_v =P(t_{(47)}>2.744)=0.0043  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=2.1 represent the mean

s=1.01 represent the sample standard deviation

n=48 sample size  

\mu_o =1.7 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 1.7, the system of hypothesis would be:  

Null hypothesis:\mu \leq 1.7  

Alternative hypothesis:\mu > 1.7  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.1-1.7}{\frac{1.01}{\sqrt{48}}}=2.744    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=48-1=47  

Since is a one side test the p value would be:  

p_v =P(t_{(47)}>2.744)=0.0043  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is higher than 1,7 entrees per order at 2% of signficance.  

4 0
3 years ago
Read 2 more answers
Find the value of x in the equation below. 2.7+x=11.7
forsale [732]

Answer:

the answer is 9

Step-by-step explanation:

4 0
3 years ago
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If (-2, y) lles on the graph of y = 3^x, then y =
sweet [91]
<h3>Answer:</h3>

\frac{1}{9}

<h3>Step-by-step explanation:</h3>

We know that x=-2, so substitute that into the equation. y=3^{-2}

With negative powers, instead of making the result negative, you divide one by it.  Mathematically speaking, x^{-y}=\frac{1}{x^y}.  This makes our equation: y=\frac{1}{3^2}

Finally, simplify the exponent. y=\frac{1}{9}

8 0
3 years ago
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the Marked price of a mobile is rupees 3500 and the shopkeeper allows 10% discount how much should the customer pay for it after
Papessa [141]

Answer:

3500 - 10% = 3150 rupees

Step-by-step explanation:

the customer will pay 3150 rupees

3 0
2 years ago
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