Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
B
Step-by-step explanation:
B is in Quadrant III.
B is the answer.
5/8=0.625
4 and 5/8=4+5/8=4+0.625=4.625
you can just seperate the fractions and add
Answer: 22,084,920 different clubs
Step-by-step explanation:
The club must have 6 juniors and 8 seniors
We have a total of 13 juniors and 16 seniors.
Now, we know that the possible combinations of N objects into a group of K is equal to:
For the juniors we have N = 13 and K = 6
For the seniors we have N = 16 and K = 8
Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:
C = Cj*Cs = 1,716*12,870 = 22,084,920
Answer:
SEE BELOW
Step-by-step explanation:
1. find value of m
a^2 + b^2 = c^2
7.5^2+10^2=c^2
15+100=c^2
115=c^2
square it
=10.7 (not answer)
a^2+b^2=c^2
10.7^2+30^2=c^2
114.49+900=c^2
1014.49=c^2
square it
m=31.9
2.20^2 + 21^2 = 841
29^2=841
yes the triangle is right angled !!!
hope this helps :)
