We need a combination of coins that equal 65 cents.
The easiest one is 13 nickels.
Another combination is 6 dimes and 1 nickel.
A third is 2 quarters, 1 dime, and 1 nickel.
The list goes on.
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hope it helps
a) We know that the probability Jane will win is 0.2, and draws is 0.3, which leaves the probability of her losing to be 0.5 (1 - 0.2 - 0.3 = 0.5).
I'll begin by filling in for the first game:
win = 0.2, draw = 0.3, lose = 0.5
Next, we'll fill in for if she wins, draws, or loses the second game. The probabilities would be the same as the first game for the second game.
Win (0.2): win = 0.2, draw = 0.3, lose = 0.5
Draw (0.3): win = 0.2, draw = 0.3, lose = 0.5
Lose (0.5): win = 0.2, draw = 0.3, lose = 0.5
b) To find the probability that Jane will win both games, we need to multiply the probability of Jane winning the first game by the probability of her winning the second game.
0.2 x 0.2 = 0.04
Hope this helps! :)
