Another question (picture)

Mathematics

1 answer:

ASHA 777 [7]3 years ago

8 0

$\left( 16 x^8 y^{-12} \right)^{\frac 1 2} = 16^{\frac 1 2} (x^8)^{\frac 1 2} (y^{-12})^{\frac 1 2} = 4 x^4 y^{-6} = \dfrac{4 x^4}{y^6}$

Third choice

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