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3 years ago

Why is 18:3 and 6:1 equivalent ratios

Mathematics

2 answers:

uranmaximum [27]3 years ago

8 0

Because 18:3 simplified is 6:1

Keith_Richards [23]3 years ago

8 0

Answer:

Because if you multiply 6 three times, it comes out to be 18.

So basically, 6 x 3 = 18

To be sure, 18 ÷ 6 = 3

So, 18:3 = 6:1

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horrorfan [7]

You should value it at 2 plus 4

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2 years ago

Select the correct answer.

yuradex [85]

Answer:

awser 29

Step-by-step explanation:

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2 years ago

The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordina

valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

$M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

$(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5$

So, the coordinates of B is (-8,-5).

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2 years ago

A university cafeteria wants to know the proportion of its 13,500 university students that prefer to eat organic foods. The cafe

Anuta_ua [19.1K]

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Step-by-step explanation:

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2 years ago

Determine the type(s) of the triangle with the given coordinates. X(6,1) Y(-2,-3) Z(0,3)

jeyben [28]

The triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

The given coordinates are X(6,1) Y(-2,-3) Z(0,3).

<h3>What are coordinates?</h3>

A coordinate system is a system in geometry that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold, such as Euclidean space, in a unique way.

We know that, Distance formula $=\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1} )^{2} }$