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schepotkina [342]
3 years ago
14

Write five names of 132

Mathematics
2 answers:
Kipish [7]3 years ago
5 0
Eleven dozens
one hundred and thirty two
6 x 22
44 x 3
100+30+2
NemiM [27]3 years ago
4 0
132
1). one hundred and thirty two.
2).100 + 30 + 2
3).1.32 x 10^2
4). 44 x 3 = 132
5). 264 divided by 2 = 132
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Solve the following systems of equations 2a+4b+c=5 ; a-4b=-6 ; 2b+c=7.
SOVA2 [1]

Answer:

a = -2

b = 1

c = 5

Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

or

a = 4b - 6 .............(2)

2b + c = 7

or

c = 7 - 2b   ...........(3)

substituting 2 and 3 in  1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

or

8b - 12 + 4b + 7 - 2b = 5

or

10b - 5 = 5

or

b = 1

substituting b in 2, we get

a = 4(1) - 6

or

a = -2

substituting b in 3, we get

c = 7 - 2(1)

or

c = 5

thus,

a = -2

b = 1

c = 5

8 0
3 years ago
pls help! :) it’s my first day knowing about this things, i don’t even think we had a lesson on it— anywayysss
podryga [215]

Answer:

acute and equilateral

Step-by-step explanation:

because all the angles are given equal

3 0
3 years ago
Read 2 more answers
An article reports the following data on yield (y), mean temperature over the period between date of coming into hops and date o
skelet666 [1.2K]

Answer:

x1=c(16.7,17.4,18.4,16.8,18.9,17.1,17.3,18.2,21.3,21.2,20.7,18.5)

x2=c(30,42,47,47,43,41,48,44,43,50,56,60)

y=c(210,110,103,103,91,76,73,70,68,53,45,31)

mod=lm(y~x1+x2)

summary(mod)

R output: Call:

lm(formula = y ~ x1 + x2)

Residuals:  

   Min      1Q Median      3Q     Max

-41.730 -12.174   0.791 12.374 40.093

Coefficients:

        Estimate Std. Error t value Pr(>|t|)    

(Intercept) 415.113     82.517   5.031 0.000709 ***  

x1            -6.593      4.859 -1.357 0.207913    

x2            -4.504      1.071 -4.204 0.002292 **  

---  

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  

Residual standard error: 24.45 on 9 degrees of freedom  

Multiple R-squared: 0.768,     Adjusted R-squared: 0.7164  

F-statistic: 14.9 on 2 and 9 DF, p-value: 0.001395

a).  y=415.113 +(-6.593)x1 +(-4.504)x2

b). s=24.45

c).  y =415.113 +(-6.593)*21.3 +(-4.504)*43 =81.0101

residual =68-81.0101 = -13.0101

d). F=14.9

P=0.0014

There is convincing evidence at least one of the explanatory variables is significant predictor of the response.

e).  newdata=data.frame(x1=21.3, x2=43)

# confidence interval

predict(mod, newdata, interval="confidence")

#prediction interval

predict(mod, newdata, interval="predict")

confidence interval

> predict(mod, newdata, interval="confidence",level=.95)

      fit      lwr      upr

1 81.03364 43.52379 118.5435

95% CI = (43.52, 118.54)

f).  #prediction interval

> predict(mod, newdata, interval="predict",level=.95)

      fit      lwr      upr

1 81.03364 14.19586 147.8714

95% PI=(14.20, 147.87)

g).  No, there is not evidence this factor is significant. It should be dropped from the model.

4 0
3 years ago
Find the value of x​
steposvetlana [31]

Answer:

x=3

Step-by-step explanation:

6x+6/32=9x-9/24

144x+144=288x-288

144x=288x-432

-144x=-432

Therefore, x=3

6 0
3 years ago
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State if the triangle in each pair are similar. If so, state the reason they are similar and complete the similarity statement.
leva [86]

Answer:

NO

Step-by-step explanation:

fe\neqcb

fg\neqbd

7 0
3 years ago
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