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3 years ago

Which gas is produced when Mg(s) is added to HCl(aq)?O2H2Cl2CO2

Chemistry

2 answers:

Rainbow [258]3 years ago

7 0

The gas produced when the two combine is h2

g100num [7]3 years ago

4 0

Answer: $H_2$ or Hydrogen

Explanation:-

$Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)$

This is a single replacement reaction in which magnesium replaces hydrogen from its aqueous solution. As magnesium is more reactive than hydrogen , it easily loses electrons to convert to $Mg^{2+}$ in $MgCl_2$ and $H^+$ in $HCl$ accepts electrons to form $H_2$ .

Thus magnesium when dropped into an aqueous solution of $HCl$ releases hydrogen gas.

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The speed of light is 3.0 x 10^8 m.s^-1. what is the speed in nm.ms^-1 ?

snow_lady [41]

Answer:

$c=3\times 10^{17}\ nm/s$

Explanation:

The speed of light is $3\times 10^8\ m/s$ . It is required to convert it into nm/s.

The relation between nm and m is as follows :

$1\ nm=10^{-9}\ m\\\\1\ m=10^9\ nm$

So,

$c=3\times 10^8\ m/s \\\\c=3\times 10^8\times 10^9\ nm/s\\\\c=3\times 10^{17}\ nm/s$

So, the speed of light is $3\times 10^{17}\ nm/s$ .

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3 years ago

In a fusion reaction, a major problem related to causing the nuclei to fuse into a single nucleus is the

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Explanation:

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As it is known that a nucleus contains protons and neutrons. So when nuclei of two atoms combine together then there will be repulsion between the protons due to the presence of like charges. As neutrons have no charge so there will be no attraction or repulsion between neutrons of two nuclei.

Thus, we can conclude that in a fusion reaction, a major problem related to causing the nuclei to fuse into a single nucleus is the repulsion of nuclei.

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3 years ago

Which of the following categories of small bodies in the solar system does Ceres belong to?

Natalija [7]

Ceres is a dwarf planet, so A.

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3 years ago

Determine the moles of H+ reacting with the metal based on the following experimental data. 10.00 mL of 1.00 M HCl solution is a

musickatia [10]

Answer:

Approximately $1.876 \times 10^{-3}\; \rm mol$ .

Explanation:

Convert both volumes to standard units (that is: liters.)

$10.00 \; \rm mL = 10.00 \times 10^{-3}\; \rm L = 1.000 \times 10^{-2}\; \rm L$ .
$27.08 \; \rm mL = 27.08 \times 10^{-3}\; \rm L = 2.708 \times 10^{-2}\; \rm L$ .

Number of moles of $\rm HCl$ initially present (in the $10.00\; \rm mL$ solution at $1.00\; \rm M$ .)

$n(\mathrm{HCl}, \, \text{initial}) = \displaystyle c \cdot V = 1.00\times 1.000 \times 10^{-2}= 1.000\times 10^{-2}\; \rm mol$ .

Number of moles of $\rm NaOH$ from the titration:

$n(\mathrm{NaOH}) = c \cdot V = 0.30 \times 2.708 \times 10^{-2} = 8.124 \times 10^{-3}\; \rm mol$ .

$\rm NaOH$ neutralizes $\rm HCl$ at a $1:1$ ratio:

$\rm HCl + NaOH \to NaCl + H_2O$ .

Hence, $n(\mathrm{HCl},\, \text{leftover}) = n(\mathrm{NaOH}) = 8.124 \times 10^{-3}\; \rm mol$ .

$\begin{aligned}&n(\mathrm{HCl},\, \text{consumed}) \\ =& n(\mathrm{HCl},\, \text{initial}) - n(\mathrm{HCl},\, \text{leftover}) \\ =& 1.000\times 10^{-2} - 8.124\times 10^{-3} \\ =& 1.876 \times 10^{-3}\; \rm mol\end{aligned}$ .

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3 years ago

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malfutka [58]

B.cell membrane is the answer

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3 years ago

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