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3 years ago

Need help with 15-17

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

4 0

For 15 the answer is 8

for 16 the answer is 9

for 17 the answer is 1

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blagie [28]

Answer:

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Step-by-step explanation:

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3 years ago

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What is 21 1/4% expressed as a fraction? 13/200 17/80 21/80 17/40

natta225 [31]

The answer is 17/80
Step by step:
Move decimal 2 to the left,
.2125
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3 years ago

Using similar triangles, what is x?

Lady bird [3.3K]

$\dfrac{x}{2.5}=\dfrac{x+2.4}{2.5+2}\\
\dfrac{x}{2.5}=\dfrac{x+2.4}{4.5}\\
4.5x=2.5(x+2.4)\\
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3 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

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3 years ago

In a random sample of 85 people attending a workshop, 63 of the respondents said the workshop was useful. What is the sample pro

SVETLANKA909090 [29]

Divide the number of respondents saying it was useful by the total number
63/85 = 0.74

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