Based on the sequence -13, -8, -3, 2, 7, 12 what will be the 500th term?

Mathematics

2 answers:

jeka943 years ago

4 0

Answer:

2482

Step-by-step explanation:

aivan3 [116]3 years ago

3 0

Answer:

2482

Step-by-step explanation:

Because this sequence starts with -13 and adds 5 each time, the 500th term will be 5(499)-13=2482. Hope this helps!

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Solve for x<br><img src="https://tex.z-dn.net/?f=6x%20-%202%20%3D%204x%20%2B%2013" id="TexFormula1" title="6x - 2 = 4x + 13" alt

solniwko [45]

x = $\frac{15}{2}$

subtract 4x from both sides of the equation

6x - 4x - 2 = 13

2x - 2 = 13

add 2 to both sides

2x = 13 + 2 = 15

divide both sides by 2

x = $\frac{15}{2}$

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3 years ago

What is the solution to the system of linear equations represented by the matrix below?

olga_2 [115]

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3 years ago

Read 2 more answers

Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.