<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
We have that
2sin²<span>x - sinx - 3 = 0
</span>
Let
A------> sin x
so
2A²-A-3=0
using a graph tool-----> to resolve the second order equation
see the attached figure
the solutions are
A=-1
A=1.5------> is not solution because sin x <span>can not be 1.5
the solution is
A=-1
therefore
sin x=-1
x=arc sin(-1)=-90</span>°
the answer is
sin x=-1x=-90° or 270°
Answer:
x = 10
Explanation:
Using Pythagoras Theorem:
Solve:
8² + 6² = x²
x² = 64 + 36
x² = 100
x = √100
x = 10
Answer:
0
Step-by-step explanation:
5(2x + 2) = 10
10x + 10 = 10
10x = 0
x = 0
It is c because I had this question on the test