The empirical formula : Fe₂O₃
<h3>Further explanation</h3>
Given
34.97g of Iron
15.03g of Oxygen
Required
The empirical formula
Solution
Mol ratio :
Fe(Iron) : 34.97 g : 56 g/mol = 0.624
O(Oxygen) : 15.03 g : 16 g/mol = 0.939
Divide by 0.624 :
Fe : O = 1 : 1.5
Fe : O = 2 : 3
Answer:
Explanation:
Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.
PT = Poxygen +Pwater
At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)
762 mmHg = Poxygen + 21.1 mmHg
Poxygen = 762 mmHg - 21.1 mmHg
Poxygen =741 mmHg
Convert the corrected pressure to atmospheres.
(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm
Use the ideal gas law to find out how many moles of gas were produced:
PV = nRT (remember to put volume in liters and temperature in Kelvin)
(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)
n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)
n = 7.69 X 10-4 mol
Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.
(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g
Answer:
Explanation:
Hello,
In this case, since the work done at constant pressure as in isobaric process is computed by:
Thus, given the pressure, initial volume and work, the final volume is:
Whereas the pressure must be expressed in Pa as the work is given in J (Pa*m³):
And the volumes in m³:
Thus, the final volume turns out:
Best regards.
Answer:
This question begins with something, you should know: molar mass from water is aproximately 18 g/m, so if 18 grams of water are contained in 1 mole, the 40 grams occuped 2.22 moles. As you see, opcion a is the best!
Explanation:
Explanation:
this molecule is a compound
its chemical formula is NaCO3H
