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3 years ago

To ensure its survival, any species must be able to

Chemistry

2 answers:

musickatia [10]3 years ago

7 0

Answer:

Explanation: Reproduce successfully. On the species level, this is what is required to avoid extinction. Individuals need to do the first two, but indivuals dying does not necessarily doom the species as a whole.

slavikrds [6]3 years ago

6 0

I believe the answer your looking for is reproduce

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2Na3N3 -> 2Na + 3N2<br><br> if 0.58 mol if NaN3 reacts, what mass of nitrogen would result

Ronch [10]

Answer:

Mass = 24.36 g of N₂

Explanation:

The balance chemical equation for the decomposition of NaNO₃ is as follow;

2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

2 moles of NaNO₃ produces = 3 moles of N₂

So,

0.58 moles of NaNO₃ will produce = X moles of N₂

Solving for X,

X = 3 mol × 0.58 mol / 2 mol

X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

8 0

3 years ago

A student carefully pipets 10.00ml of ethanol into a beaker. If ethanol has a density of 0.779g/ml, how many grams of ethanol we

lesantik [10]

Answer: 7.79 grams of ethanol were put into the beaker.

Explanation:

To calculate the mass of ethanol, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of ethanol = 0.779 g/mL

Volume of water = 10.00 mL

Putting values in above equation, we get:

$0.779g/mL=\frac{\text{Mass of ethanol}}{10.00mL}\\\\\text{Mass of ethanol}=(0.779g/mL\times 10.00mL)=7.79g$

Thus 7.79 grams of ethanol were put into the beaker.

5 0

3 years ago

you are holding a bowling ball with a mass of 6 kg at a height of 1 meter. How much gravitational potential energy does the bowl

Bumek [7]

The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,

PE=mgh

PE=(6 kg)(9.8 m/s^2)(1 m)

PE=58.8 kg•m^2/s^2 or 58.8 Newtons

The GPE of the bowling ball under these conditions would be about 59 Newtons.

Hope this helps!

7 0

4 years ago

Why are animal vaccinated?

juin [17]

Answer:

to go against dangerous viral and bacteria

Explanation:

5 0

3 years ago

Read 2 more answers

A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati

Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.

$\text{calculating the initial HI}= \frac{mol}{V}$

$=\frac{9.3 \times 10 ^ -3}{2}$

$=0.00465 \ Mol$

$\text{Similarly}\ \ I_2 \ \ \text{follows} \ \ H_2 = 0 }$

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

$HI = 0.00465 - 2x\\\\ I_{2} \ eq = H_2 \ eq = 0 + x \\\\$

It is defined that:

$I_2 = 6.29 \times 10^{-4} \ M \\\\x = I_2 \\\\$

$HI \ eq= 0.00465 - 2x \\$

$=0.00465 -2 \times 6.29 \times 10^{-4} \\\\ = 0.00465 -\frac{25.16 }{10^4} \\\\ = 0.003392\ M$

Now, we calculate the position:

For the reaction $H 2(g) + I 2(g)\rightleftharpoons 2HI(g)$ , you can calculate the value of Kc at 1000 K.

data expression for Kc

$2HI \rightleftharpoons H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}$

$= \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386$

calculating the reverse reaction

$H_2(g) + I_2(g)\rightleftharpoons 2HI(g)$

$Kc = \frac{1}{Kc} \\\\$

$= \frac{1}{0.034386}\\ \\= 29.081\\$

7 0

3 years ago