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olganol [36]
3 years ago
12

To ensure its survival, any species must be able to

Chemistry
2 answers:
musickatia [10]3 years ago
7 0

Answer:

B

Explanation: Reproduce successfully. On the species level, this is what is required to avoid extinction. Individuals need to do the first two, but indivuals dying does not necessarily doom the species as a whole.

slavikrds [6]3 years ago
6 0
I believe the answer your looking for is reproduce
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Consider the resonance structures of formate. the first lewis structure of formate has a central carbon atom. a hydrogen atom an
OleMash [197]
So,

Formate has a resonating double bond.

In molecular orbital theory, the resonating electrons are actually delocalized and are shared between the two oxygens.  So the carbon-oxygen bonds can be described as 1.5-bonds (option B).  I'm not sure if option C is correct, however, because the likelihood of both delocalized electrons being in the area of one oxygen atom is less than 50%.<span />
6 0
3 years ago
Name at least 4 other gases in the atmosphere besides oxygen and nitrogen
BartSMP [9]
<span><span>Argon,</span><span>Carbon dioxide,</span><span>Neon,</span><span>Helium, and </span><span>Methane</span></span>
5 0
3 years ago
Read 2 more answers
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
velikii [3]

Answer:

[Br₂] =  1.25M

Explanation:

        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

Eq    0.80M            ?                0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0
3 years ago
What is the coefficient of silver in the final, balanced equation for this reaction?
vekshin1

This is an incomplete question, the complete question is attached below.

Answer : The coefficient of silver in the final, balanced equation for this reaction is, 3

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given redox reaction is,

Ag^+(aq)+Al(s)\rightarrow Ag(s)+Al^{3+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : Al\rightarrow Al^{3+}+3e^-

Reduction : Ag^{+}+1e^-\rightarrow Ag

In order to balance the electrons, we multiply the reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

The balanced redox reaction will be,

3Ag^+(aq)+Al(s)\rightarrow 3Ag(s)+Al^{3+}(aq)

From the balanced redox reaction we conclude that, the coefficient of silver in the final balanced equation for this reaction is 3.

Hence, the correct option is 3.

8 0
3 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
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