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emmasim [6.3K]
3 years ago
8

formation of bubbles can be associated with physical changes under certain contexts. provide examples of specific substances and

describe the situations in which bubbles form during a physical change and a chemical change.
Chemistry
1 answer:
ira [324]3 years ago
6 0
Sorry bro don’t know same boat u in
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Which step in the scientific method requires you to use your senses to obtain information?
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The answer is Observation.

For you to observe the things around you then you need to use all your sense organs....

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write a chemical equation for the ionization of water. how do you indicate that this is a reversible action?
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H₂O + H₂O ⇌ H₃O⁺ + OH⁻

You use two single-barbed arrows pointing in opposite directions (technically rightwards harpoon over leftwards harpoon) <em>to indicate a reversible reactio</em>n.


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Which layer of the skin lacks blood vessels?
marusya05 [52]

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Epidermis

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The epidermis lacks blood vessels.

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In the kinetic theory of matter how does temperature affect the particles?
Scorpion4ik [409]

Answer:

B- Lower temperature causes a reduction in movement

Explanation:

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3 0
3 years ago
Calculate the total heat required (in joules) to convert 3.95 grams liquid ethanol (C2H5OH) at 25.0 °C to gas at 95.0 °C, given
kumpel [21]

Answer:

The total heat required is 4088.6 J

Explanation:

We have three processes which involve heat absorption. We have to calculate the heat of each process and then to calculate the total heat.

1- liquid ethanol is heated from 25ºC (298 K) to the boiling point 78.5ºc (351.5 K). We use specifi heat of liquid ethanol to calculate the heat absorbed in this part:

H1= m x Sh x ΔT

H1= m x Sh x (Tfinal - Tinitial)

H1= 3.95 g x 2.45 J/g.K x (351.5 K -298 K)

H1= 517.7 J

2- State change: liquid ethanol is vaporized it turns gaseous ethanol The process occur at constant temperature (78.5ºC= 351.5 K). We need the molecular weight of ethanol (2 x 14 + 5 + 16 + 1= 46 g/mol) to cancel mol unit:

H2= m x ΔHvap x 1/Mw

H2= 3.95 g x 40.5 KJ/mol x 1 mol/46 g

H2= 3.477 KJ= 3477 J

3- Gaseous ethanol is heated from 78.5ºC to a final temperature of 95ºC (368 K). We use the specific heat of gaseous ethanol:

H3= m x Sh x ΔT

H3= 3.95 g x 1.43 J/g.K x (368 K - 351.5 K)

H3= 93.2 J

The total heat required is calculated as follows:

Htotal= H1 + H2 + H3

Htotal= 517.7 J + 3477.7 J + 93.2 J

Htotal= 4088.6 J

6 0
3 years ago
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