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BaLLatris [955]
3 years ago
15

Supposed the population of deer in a region was 3,500 in the year 2000.since then population has grown by 3.5% annually. What wi

ll the approximate population be in the year 2020? Y=a•b^x where a is the starting amount, b is the growth rate (increasing add to 1),and x is time.
Mathematics
1 answer:
sergejj [24]3 years ago
3 0
Y = a (b^x)

1) x = 0, y = 3500

=> 3500 = a (b^0)

=> 3500 = a (1)

=> a = 3500

2) growth percent = 3.5% => growth rate = 1.035 = b

=> y = 3500 (1.035)^ x

3) year 2020 => x = 2020 - 2000 = 20

4) y = 3500 (1.035)^ 20 = 6964

Answer: 6964.

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8 0
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The sum of two consecutive integers is 65. Find the two integers.
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8 0
3 years ago
What is -2(g+5) please help :)
Nastasia [14]

Answer:

-2g -10

Step-by-step explanation:

On simplifing this expression we get,

-2(g+5)

=> -2g + (-10)

=> -2g - 10

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

6 0
2 years ago
Read 2 more answers
Solve for 50 points<br> x^(2)=100
Eddi Din [679]

x²=100

x²=10×10

x=10

hope it helps you

7 0
3 years ago
Read 2 more answers
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