A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
<span>BusinessComputersEnglishForeign LanguagesHealthHome EconomicsMathMusicPhysical EducationScienceSocial Studies</span>GRADE LEVELS<span>PreschoolKindergartenElementary School1st Grade2nd Grade3rd Grade4th Grade5th Grade6th Grade7th Grade8th GradeHigh School9th Grade10th Grade11th Grade12th GradeCollegeAdult Education</span><span>Post a New QuestionCurrent Questions</span><span>Homework Help: Math: Algebra</span>Recent Homework Questions About Algebra
pre algebra
The ball game took in $1,920 one Saturday. The number of $12 adult tickets was 15 more than twice the number of $5 child tickets.of spray. how much
9514 1404 393
Answer:
(5 15/20) -(2 8/20) = 3 7/20
Step-by-step explanation:
Problems in "least common denominator" are made much easier if you are familiar with your times tables.
When you compare the denominator 4 to the denominator 20, you see that ...
20 = 5 × 4
An equivalent fraction is made by multiplying by 1. Here, the version of 1 you want for the top fractions is 5/5.

Similarly, the bottom fraction has its denominator multiplied by 4 to get from 5 to 20. The equivalent fraction is found by multiplying the numerator by the same number.

Then the desired difference is ...
