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3 years ago

A) What is the equation of line A b) What is the equation of line B

Mathematics

1 answer:

dsp733 years ago

7 0

Answer:

the equation of line a is y = 4

The equation of line b is x=8

Step-by-step explanation:

Line A -is a horizontal line with no slope - for every value of x no matter what x is - y= 4

Line B has an infinite slope because it is vertical

For every value of y - no matter what y you choose x= 8 So the equation of the line is x=8

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

Q#1 please help t o resolve

Veseljchak [2.6K]

Answer: option. y=-1.33x; 2.67

Solution:

If y varies directly with x, the relation between y and x is:

y=kx

where k is a constant of proporcionality.

We know y=8 when x=-6. Replacing these values in the equation above:

8=k(-6)

8=-6k

Solving for k: Dividing both sides of the equation by -6:

8/(-6)=-6k/(-6)

-1.33=k

k=-1.33

Then the relation between y and x is:

y=kx→y=-1.33x

What is the value of y when x=-2?

Replacing x by -2 in the formula:

y=-1.33x→y=-1.33(-2)→y=2.66

3 0

3 years ago

One side of a triangle is 2 times the second side. The third side is 15 feet longer than the second side. The perimeter of a

ch4aika [34]

Answer:

16, 8, 23

Step-by-step explanation:

2x+x+x+15=47

4x+15=47

4x=32

x=8

2x=16

x+15=23

7 0

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The maritime museum has 100 ship models. Visitors can see 90% of the ships in a special exhibit. How many ships can visitors see

DochEvi [55]

90% of 100 = 0.9 x 100 = 90

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Answer: The visitor can see 90 ships.
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Consider the figure below where l2 intersects l1 and m∠2=90°.

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