9514 1404 393
Answer:
(3) 12
Step-by-step explanation:
Let x represent the length of leg XY. Then the length of YZ is x/2 and the area of the right triangle is ...
A = 1/2bh
A = 1/2(x)(x/2) = x²/4
36 = x²/4 . . . . . use the given value for area
144 = x² . . . . . . multiply by 4
√144 = 12 = x . . . . . take the square root
The length of leg XY is 12 cm.
-20 + y = 2
y = 22
20 + 3y = 6
y = 14/3
The answer is 3 divided by 1/2
Answer:
A. -¾ + 0 = -¾
B. -¾ - ¾ = -(¾ + ¾)
C. ¾ - ¾ = ¾ + (-¾)
E. -¾ + ¾ = ¾ + (-¾)
F. -¾ + ¾ = 0
Step-by-step explanation:
Let's check each equation to determine whether they are true or false.
If what we have in the both sides are equal, then the equation is true, if they're not, them it is false.
✔️-¾ + 0 = -¾
Add everything on your left together
-¾ = -¾ (TRUE)
✔️-¾ - ¾ = -(¾ + ¾)
Add everything on both sides together respectively
(-3 - 3)/4 = -(3 + 3)/4
-6/4 = -6/4 (TRUE)
✔️¾ - ¾ = ¾ + (-¾)
0 = ¾ - ¾ (+ × - = -)
0 = 0 (TRUE)
✔️-¾ + ¾ = ¾ - (-¾)
0 = ¾ + ¾ (- × - = +)
0 = 6/4 (FALSE)
✔️-¾ + ¾ = ¾ + (-¾)
0 = ¾ - ¾ (+ × - = -)
0 = 0 (TRUE)
✔️-¾ + ¾ = 0
0 = 0 (TRUE)
Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
