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3 years ago

When gasoline is burned in a car engine,_ energy is converted into _ energy.

2 answers:

8 0

<span>Chemical Energy is converted into Mechanical Energy.

</span>When gasoline is burned in a car engine, chemical energy is converted into mechanical energy.

My name is Ann [436]3 years ago

8 0

Answer: D

Explanation: When gasoline is burned in a car engine,chemical energy is converted into mechanical energy.

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Light enters air from water. The angle of refraction will be A. less than the angle of incidence. B. greater than or equal to th

Rina8888 [55]

Answer:

E. greater than the angle of incidence.

Explanation:

Snell's law states that:

$n_i sin \theta_i = n_r sin \theta_r$ (1)

where

$n_i, n_r$ are the refractive index of the first and second medium

$\theta_i, \theta_r$ are the angle of incidence and refraction, respectively

For light moving from water to air, we have:

$n_i = 1.33$ (index of refraction of water)

$n_r = 1.00$ (index of refraction of air)

Substituting into (1) and re-arranging the equation, we get

$\sin \theta_r = \frac{n_i}{n_r} sin \theta_i = 1.33 sin \theta_i$

which means that

$\theta_r > \theta_i$

so, the correct answer is

E. greater than the angle of incidence.

4 0

3 years ago

Read 2 more answers

The energy of atoms and molecules in an object due to their motion is_______ energy

QveST [7]

I think the answer is potential

7 0

3 years ago

The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how

liraira [26]

Answer:

$x = 0.198456 \ m$

$h = 1.3061 \ m$

$v = 5.06 \ m/s$

$d = 4.0273 \ m$

Explanation:

Considering the first question

From the question we are told that

The spring constant is $k = 32.50 N/m$

The potential energy is $PE = 0.640 \ J$

Generally the potential energy stored in spring is mathematically represented as $PE = \frac{1}{2} * k * x^2$

=> $0.640= \frac{1}{2} * 32.50 * x^2$

=> $x = \sqrt{0.03938}$

=> $x = 0.198456 \ m$

Considering the second question

From the question we are told that

The mass of the dart is m = 0.050 kg

Generally from the law of energy conservation

$PE = mgh$

=> $0.640 = 0.050 * 9.8 * h$

=> $h = 1.3061 \ m$

Considering the third question

The height at which the dart was fired horizontally is $H = 3.90\ m$

Generally from the law of energy conservation

$PE = KE$

Here KE is kinetic energy of the dart which is mathematical represented as

$KE = \frac{1}{2} * mv^2$

=> $0.640 = \frac{1}{2} * 0.050 * v^2$

=> $v^2 = 25.6$

=> $v = 5.06 \ m/s$

Considering the fourth question

Generally the total time of flight of the dart is mathematically represented as

$t = \frac{ 2 * H }{g}$

=> $t = \frac{ 2 * 3.90 }{9.8 }$

=> $t = 0.7959 \ s$

Generally the horizontal distance from the equilibrium position to the ground is mathematically represented as

$d = v * t$

=> $d = 5.06 * 0.7959$

=> $d = 4.0273 \ m$

5 0

3 years ago

A person wants to make a metronome for music practice. He uses a 35-g object attached to a spring to serve as the time standard.

alukav5142 [94]

To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Here,

k = Spring constant

m = Mass

Our values are given as,

$m = 35g = 35*10^{-3}kg$

$f = 1 Hz$

Rearranging to find the spring constant we have that,

$k = (2\pi f \sqrt{m})^2$

$k = 4\pi^2 f^2 m$

$k = (4) (\pi)^2 (1) (35*10^{-3})$

$k = 1.38N/m$

Therefore the spring constant is 1.38N/m

7 0

3 years ago

A passenger jet travels from Los angles to Bombay, India, in 22 h. The return flight takes 17 h. The difference in flight times

Hoochie [10]

Answer:

70.5 mph

Explanation:

A passenger jet travels from Los Angeles to Bombay, India, in 22h.

The return flight takes 17 h.

The difference in flight times is caused by winds over the Pacific Ocean that

blow primarily from west to east.

If the jet's average speed in still air is 550 mi/h what is the average speed

of the wind during the round trip flight? Round to the nearest mile per hour.

Is your answer reasonable?

Let w = speed of the wind

Write a distance equation (dist is the same both ways

17(550+w) = 22(550-w)

9350 + 17w = 12100 - 22w

17w + 22w = 12100 - 9350

39w = 2750

W = 2750/39

w = 70.5 mph seems very reasonable

Confirming if the solution by finding the distances using these value

17(550+70.5) = 10549 mi

22(550-70.5) = 10549 mi; confirms our solution of w = 70.5 mph

6 0

3 years ago

When gasoline is burned in a car engine,_____ energy is converted into _____ energy.

When gasoline is burned in a car engine,_ energy is converted into _ energy.