Question

In an experiment, you determined the density of the wood to be 0.45g/cc, whereas the standard value was 0.47g/cc. Determine the percentage difference. [Hint: Look at the procedure section of Part Al[1 Point] 5. 6. How do you determine y-intercept from a graph? [1 Point]

Answer 1

Answer:

Percentage difference is 4.25 %.

Explanation:

Standard value of the density of wood, $\rho_s=0.47\ g/cc$

Experimental value of the density of wood, $\rho_e=0.45\ g/cc$

We need to find the percentage difference on the density of wood. It is given by :

$\%=|\dfrac{\rho_s-\rho_e}{\rho_s}|\times 100$

$\%=|\dfrac{0.47-0.45}{0.47}|\times 100$

Percentage difference in the density of the wood is 4.25 %. Hence, this is the required solution.