Answer:
self-inductance is 23.4 mH
0.145 seconds it be turned off
Explanation:
given data
length L = 42.2 cm
diameter d = 10 cm
no of loop N = 1000 loops
induced emf = 3 V
current I = 18.6 A
to find out
self-inductance and How fast it turned off emf
solution
we apply here formula of self-inductance that is
self-inductance = u×N²×A / L .......................1
put here value
self-inductance = 4π×1000²×(π×r² / 0.422)
self-inductance = 4π×1000²×(π×0.05² / 0.422)
self-inductance = 0.0234 H
so self-inductance is 23.4 mH
and
we know emf = Ldi /dt
so time = 0.0234 × 18.6
time = 0.145 seconds
