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Citrus2011 [14]
3 years ago
7

The formulas for these two ?

Physics
1 answer:
Usimov [2.4K]3 years ago
3 0

Answer:

These are called kinematics equations.

Explanation:

These equations are used when there is either a constant velocity motion or a constant acceleration motion.

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A 80 mW laser beam is polarized horizontally. It then passes through two polarizers. The axis of the first polarizer is oriented
inn [45]

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

The E(incident) for the second  polarizer is E(incident)=12.340115991

<u>Explanation:</u>

<u>Solving the problem:</u>

<u>Given</u>

Transmitted data = 80 mW

First polarizer= 30 degree

Second polarizer= 60 degree

We have the formula,

E (transmitted) = E (incident)cos()

<u>1. Through the first polarizer</u>

E (transmitted) = E (incident)cos()

80=E(incident) cos(60 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 60 degree

E(incident)=-76.1930384332

The E(incident) for the first  polarizer is E(incident)=-76.1930384332

<u>2. Through the first polarizer</u>

We have the formula,

E (transmitted) = E (incident)cos()

80=E(incident) cos(30 degree)     (according to law subtract the given degree with 90 degree).

Then,

E(incident)=E(transmitted) cos()

E(incident) =80×cos 30 degree

E(incident) =12.340115991

The E(incident) for the second  polarizer is E(incident)=12.340115991

<u></u>

4 0
3 years ago
1. How much energy is needed to raise 1 g of water 1°C?
Serga [27]

Answer:

1.The calorie was originally defined as the amount of heat required at a pressure of 1 standard atmosphere to raise the temperature of 1 gram of water 1° Celsius. Since 1925 this calorie has been defined in terms of the joule, the definition since 1948 being that one calorie is equal to approximately 4.2 joules.

2.Boiling water at 100 degrees Celsius: 540 calories are needed to turn 1 gram (at 100 degrees Celsius) of water to steam.

5 0
4 years ago
A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.
mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

m_sv_s + m_bv_b = 0

where m_s = 2500 kg, m_b = 25 kg are masses of the ship and ball respectively. v_s = 0.25 m/s, v_b are the velocities of the ship and ball respectively, after the shooting.

2500*0.25 + 25*v_b = 0

25v_b = -2500*0.25

v_b = -2500*0.25/25 = -25 m/s

So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.

3 0
3 years ago
For every action, there is an equal and opposite reaction.
KiRa [710]

Answer:

This is newton's 3rd law

Explanation:

3 0
3 years ago
This back-and-forth movement of electrons is called . In contrast, the movement of electrons in one direction in a battery circu
stich3 [128]
The back-and-forth movement of electrons is called alternating current. Electrons go back and forth, the direction of their path alternates from one direction to another.

the movement of electrons in one direction is called direct current. The electrons move in a direct, single path without changing directions.
5 0
3 years ago
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