The answer is 86 degrees Fahrenheit. Formula is (30 x 9.5) + 32 = 86
Out of the following choices given, if you insert a piece of rubber between the wires, the electrons do not flow. The rubber material is an insulator. The correct answer is D.
Answer:
Explanation:
We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .
f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .
f will be lowest when v₀ is highest .
velocity of observer is highest when he is at the equilibrium position or at middle point .
So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .
Time should not be messed with
for bad things could happen
so think before you act or you'll regret it
Answer:
E1_max = 866 V/m...................................... option D
Explanation:
We know that for linearly polarized light, relation between intensity and electric field is given by:
I_avg = (1/2)*c*e0*E_max^2
I_avg = (1/2)*3*10^8*8.854*10^-12*1000^2
I_avg = 1328.1 W/m^2
Now given that light is already polarized, So Using Malus's law, Intensity of light after passing through polarizer will be:
I1 = I_avg*(cosФ )^2
Ф = 30 deg, So
I1 = 1328.1*(cos 30 deg)^2 = 996.1 W/m^2
Now electric field corresponding to above Intensity will be:
I1 = (1/2)*c*e0*E1_max^2
E1_max = sqrt (2*I1/(c*e0))
E1_max = sqrt (2*996.1/(3*10^8*8.854*10^-12))
E1_max = 866 V/m