Answer:
Option (2).
Step-by-step explanation:
It is given in the question,
ΔLMN is a right triangle with base LM = 3a units
Hypotenuse MN = 5a
By applying Pythagoras theorem in ΔLMN,
MN² = LM² + NM²
(5a)² = (3a)² + MN²
25a² - 9a² = MN²
MN = √16a²
MN = 4a
Therefore, vertices of the triangle will be L(0, 0), M(3a, 0) and N(0, 4a).
Option (2) will be the answer.
Answer:
15) a) 8
b) y + 2
c) y - 1
16) True
17) 2n - 1, where n is an integer
18) a) 3p + 4q
b) 500 - 3p - 4q
Answer:
incomplete
Step-by-step explanation:
please send the full information, I can't see students belonging to acers
Think: You're treating the numerator and the denom. in precisely the same way. In doing so you are NOT changing the value of the fraction, only the appearance.
Example: start with 2/3. Mult num. and den. both by 7: 14/21.
2/3 and 14/21 result in precisely the same decimal fraction, showing that the latter set of fractions is equivalent to the former set.
