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balandron [24]
3 years ago
14

A radio disc jockey has 8 songs on this upcoming hour's playlist: 3 are rock songs, 3 are reggae songs, and 2 are country songs.

The disc jockey randomly chooses the first song to play, and then she randomly chooses the second song from the remaining ones. What is the probability that the first song is a country song and the second is a reggae song?
Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

\frac{3}{28} probability.

Step-by-step explanation:

Probability:

\frac{2}{8} of choosing country first try.

\frac{3}{7} of choosing reggae without replacement.

\frac{2}{8} *\frac{3}{7} =\frac{6}{56} =\frac{3}{28}

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Answer:

\boxed{\frac{153}{100}\:\:Or\:\:1.53}

Step-by-step explanation:

Let the number be n.


Then,

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This implies that;

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We multiply both sides by \frac{3}{100} to obtain;


\frac{3}{100} \times \frac{100}{3}n=\frac{3}{100} \times 51


\Rightarrow n=\frac{3}{100} \times 51


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Or

\Rightarrow n=1.53


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