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balandron [24]
3 years ago
14

A radio disc jockey has 8 songs on this upcoming hour's playlist: 3 are rock songs, 3 are reggae songs, and 2 are country songs.

The disc jockey randomly chooses the first song to play, and then she randomly chooses the second song from the remaining ones. What is the probability that the first song is a country song and the second is a reggae song?
Mathematics
1 answer:
Artemon [7]3 years ago
4 0

Answer:

\frac{3}{28} probability.

Step-by-step explanation:

Probability:

\frac{2}{8} of choosing country first try.

\frac{3}{7} of choosing reggae without replacement.

\frac{2}{8} *\frac{3}{7} =\frac{6}{56} =\frac{3}{28}

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Pls help me with this <br>ans should be well explained ​
Snezhnost [94]

Let's observe

#1st column

  • 3+2+1+4=10

10th alphabet=J

#2nd

  • 5+9+4+6=24

24th alphabet=X

#3rd

  • 2+1+3+3=9

9 th Alpha bet=I

#4th

  • 8+4+9+5=26

26th Alphabet=Z

#5th

  • 7+3+1+2=13

13 th alphabet=M

Option B is correct

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3 years ago
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Step-by-step explanation:

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