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GuDViN [60]
4 years ago
8

When the brakes of a certain car are applied, a deceleration of 6.0 m/s is produced. How much time will it take to bring the car

to a halt from an initial speed of 110 km/hr?
Physics
1 answer:
nexus9112 [7]4 years ago
8 0
Use the formula:

V=V_o+at\\
\\
15.27=30.55-6t\\
\\
6t=30.55-15.27\\
\\
6t=15.28\\
\\
t=\frac{15.28}{6}=2.54 \ s

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allochka39001 [22]

The amount of electric current in the coil and the number of turns of wire
in the coil directly determine the strength of the electromagnet.

But the voltage of the battery determines the amount of current through
the wire, so the battery voltage is also indirectly involved.


6 0
4 years ago
A 2.99-m-long2.99-m-long rod, as measured in its rest frame, speeds by you longitudinally at 6.49×107 m/s6.49×107 m/s . You meas
Rasek [7]

Answer:

The contraction in the rod is 71 mm.

Explanation:

Given that,

original length L'= 2.99 m

Speed v= 6.49\times10^{7}\ m/s

We need to calculate the length

Using expression for length contraction

L'=\gamma L

L=\dfrac{L'}{\gamma}

Where,

\gamma=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}

L=\sqrt{1-\dfrac{v^2}{c^2}}L'

Where, v = speed of observer

c = speed of the light

Put the value into the formula

L=\sqrt{1-\dfrac{(6.49\times10^{7})^2}{(3\times10^{8})^2}}\times2.99

L=2.919\ m

The expression for the contraction in the rod

d =L'-L

d=2.99-2.919

d=0.071

d= 71\ mm

Hence, The contraction in the rod is 71 mm.

7 0
4 years ago
a scientist is creating a new synthetic material. the material’s density is 6.1 g/cm3. which sentences describe how the scientis
icang [17]
<span>A.) The scientist can decrease the mass while keeping the volume constant.
B.) The scientist can increase the mass while keeping the volume constant.
C.) The scientist can decrease the volume while keeping the mass constant.
D.) The scientist can increase the volume while keeping the mass constant.
</span>-Plato answer choices for this question 
6 0
3 years ago
Read 2 more answers
Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
Ainat [17]

Answer:

  • <em>Abbie’s acceleration is (1/2) Zak’s acceleration.</em>

Explanation

1. <u>Data</u>:

a) ω = constant

b) Abbie: r₁ = 1 m

c) Zak: r₂ = 2 m

d) Ac₁ = ? Ac₂

2. <u>Formulae</u>

  • Ac = ω² r

3. <u>Solution</u>:

a) Abbie:

  • Ac₁ = ω² r₁  =  ω² (1m)

b) Zack:

  • Ac₂ = ω² r₂  = ω² (2m)

c) Divide Ac₁ / Ac₂

  • Ac₁ / Ac₂ =  ω² (1m) / [ω² (2m) ] = 1/2

⇒      Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂

5 0
3 years ago
A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle ϕ=30∘ above the horizontal, as shown (Figure
Nesterboy [21]

Answer:

<h2>The work done is 0.882 Joules.</h2>

Explanation:

To calculate the work, we need to find all forces that are involved in the movement.

As you can analyse, the body is the force that make the box to move, and the friction force is opposite to it, we cannot forget about the friction. So, we have to calculate the resultant force to this context.

F_{R}=W_{x}-F_{k}

So, to find W_{x} we use: W_{x}=W.sen\phi; where W=2N;\phi = 30\°

W_{x}=2N.sin30\°=1\frac{1}{2}N=1N

The friction force would be:

F_{k}=\mu_{k}N=(0.30)(1.7N)=0.51

Then, the resultant force is:

F_{R}=W_{x}-F_{k}

F_{R}=1N-0.51N=0.49N

Now, we calculate the work: W=F_{R} d

W=(0.49N)(1.8m)=0.882J

Therefore, the work done is 0.882 Joules.

7 0
3 years ago
Read 2 more answers
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