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stellarik [79]
4 years ago
7

Consider two examples of electromagnetic radiation: one with a wavelength of 500 nm, and the other with a wavelength of 2 cm. Fo

r these two examples of radiation, which of the following statements are TRUE? a. The 500-nm radiation will have a higher frequency than the 2-cm radiation. b. The 500-nm radiation will have a lower frequency than the 2-cm radiation. c. The 500-nm radiation is visible to human eyes. d. The 2-cm radiation is visible to human eyes. e. The 500-nm radiation travels at the speed of light. f. The 2-cm radiation travels at the speed of light.
Physics
2 answers:
fredd [130]4 years ago
7 0

For these two examples of radiation . . .

<em>a.</em> The 500-nm radiation will have a higher frequency than the 2-cm radiation.

<em>c.</em> The 500-nm radiation is visible to human eyes.

<em>e.</em> The 500-nm radiation travels at the speed of light.

<em>f.</em> The 2-cm radiation travels at the speed of light.

Korolek [52]4 years ago
6 0

Answer:

a. The 500-nm radiation will have a higher frequency than the 2-cm radiation.

c. The 500-nm radiation is visible to human eyes.

e. The 500-nm radiation travels at the speed of light.

f. The 2-cm radiation travels at the speed of light.

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength

c is the speed of light having value 3\times 10^8\ m/s

From the above formula, Frequency and wavelength are inversely proportional to each other.

Thus,

The longer wavelength corresponds to higher frequency and vice versa.

Thus, <u>Option a is correct. </u>

a. The 500-nm radiation will have a higher frequency than the 2-cm radiation.

As 500 nm is less than 2 cm and thus it corresponds to higher frequency.

<u>Option c is correct.</u>

c. The 500-nm radiation is visible to human eyes.

Human eye can see in the visible region which corresponds to 380 - 740 nm.

<u>Option e and f are correct.</u>

e. The 500-nm radiation travels at the speed of light. f. The 2-cm radiation travels at the speed of light.

Electromagnetic waves are the waves which are created as the result of the electrical waves which are perpendicular to each other and also perpendicular to the direction of propagation.

Electromagnetic spectrum is range of the frequencies and their respective wavelengths of the various type of the electromagnetic radiation but all the radiations travel at same speed which is - 3\times 10^8\ m/s

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10.7 rad/s is the final angular velocity of the stick.

Given:

Mass of the stick = 4.42 kg

Length of the stick = 1.23m

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The linear velocity of the stick, v=\frac{I}{m}

                                                  v=\frac{12.8 N.s (\frac{1 kg m/s^2}{1 N}) }{4.42 kg}

                                                  v  = 2.89 m/s

Therefore, the final linear velocity of the stick is 2.89 m/s

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w=\frac{12 ( 12.8 N.s ) ( 46.4 cm)}{(4.42 kg) (1.23 m)^2}

w= \frac{12 (12.8 N.s) (46.4 cm) (\frac{10^-^2 m}{1 cm} )}{(4.42 kg) (1.23m)2}

w=10.7   rad/s

Therefore, 10.7 rad/s is the final angular velocity of the stick.

Learn more about linear velocity here:

brainly.com/question/15154527

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A bucket weighing 5 lbs is lifted at a constant rate from the bottom of a 100 ft well by a rope which weighs 5 lbs. The bucket h
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Answer:

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