Answer:19.34 miles
Explanation:
Given
First car travels with 32 mi/h
second travels with 54 mi/h
they leave at 2:00 Pm at 45
distance traveled by them is 0.5 hr
suppose First is traveling towards x axis and another travels 45 to it
Distance traveled by first car is
Position vector of first car after 0.5 hr
Position vector of second car after 0.5 hr
distance between them
distance between them
Mass = Weight/g
= 1225 N/9.81 m/s^2
= 124.872579 kg
(rounded-off in 3 significant figures) = 125 kg
NOTE: I truly apologize if my answer is incorrect. I still hope this helped! :) (a brainliest would be much appreciated!)
<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>