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3 years ago

Why do we get dew on the surface of a cold soft drinking bottle kept in open air?

2 answers:

5 0

There is a different in temps from the bottle to the air. Its condensation . The more colder the water or drink is the more condensation on the bottle of a hot day . COLD WATER+HOT WATER = More condensation.

JulsSmile [24]3 years ago

3 0

We see small drops of water on the bottle of a cold soft drink water kept in air because the air surrounding the bottle, when comes in contact with the cool surface of water condenses to form water, and this water is seen as drops on the bottle.

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If I push a box at a constant rate is there friction force acting on it?

yanalaym [24]

Yes, the friction is acting in the opposite direction you are pushing.

3 0

4 years ago

Hydrogen is in Group 1A of the periodic table, known as the alkali metals, although it obviously isn't a metal. What is the reas

jeka57 [31]

It's highly reactive and contains only one valence electron

6 0

3 years ago

A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th

xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

$v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}$

(b) The tension, $T$ , is given by

$v =\sqrt{\dfrac{T}{\mu}}$

where $v$ is the speed, $T$ is the tension and $\mu$ is the mass per unit length.

Hence,

$T = \mu\cdot v^{2}$

To determine $\mu$ , we need to know the mass of the cable. We use the density formula:

$\rho = \dfrac{m}{V}$

where $m$ is the mass and $V$ is the volume.

$m=\rho\cdot V$

If the length is denoted by $l$ , then

$\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}$

$T = \dfrac{\rho\cdot V}{l} v^{2}$

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

$V = \pi \dfrac{d^{2}}{4} l$

$T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2$

$T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2$

$T = 11159.4186\ldots \text{ N} = 11000 \text{ N}$

4 0

4 years ago

Scenario: You place a mug of hot tea on the table in a cool room.

Shkiper50 [21]

A. Radiation, conduction

B.
*Radiation will occur between the mug of hot tea and the room
*conduction will occur between the mug of hot tea and the table

C. The table as well as the surrounding air will become warmer.
This is because heat is given off from the mug of hot tea.

6 0

3 years ago

Show that liquid pressure is directly<br>proportional to height of liquid in a vessel.

Norma-Jean [14]

Answer:

P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)

Plugging everything in we get:

P = dAhg/A

P=dhg

So we have shown that liquid pressure is directly proportional to height of liquid in a vessel.

7 0

3 years ago