Describe how you would plot a line that has a starting point at (2,-3) and a slope of 3/4
1 answer:
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Answer:
y = x + 7
Step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
y - 8 = - (x + 5) ← is in point- slope form
with m = -
given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept ) , then
y = x + c ← is the partial equation
to find c substitute (- 6, - 2 ) into the partial equation
- 2 = - 9 + c ⇒ c = - 2 + 9 = 7
y = x + 7 ← equation of line K