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liraira [26]
4 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
1 answer:
Lunna [17]4 years ago
7 0

−5 < a − 4 < 2

+4 +4

-1 < a < 6

Answer is B. The second one


You might be interested in
Find the value of x for which allb <br> A. 35<br> B. 145<br> C. 140<br> D. 47
Paha777 [63]

Answer:

A. 35

Step-by-step explanation:

a || b .....(given)

line c is their transversal.

-> x° + (3x + 40)° = 180° (Interior angles on the same side of transversal)

-> (3x + 40 + x)° = 180°

-> (4x + 40)° = 180°

-> 4x + 40 = 180

-> 4x = 180 - 40

-> 4x = 140

-> x = 140/4

-> x = 35

7 0
2 years ago
Plz help and explain
Firdavs [7]
Id say the first one because the points just touch down
8 0
3 years ago
Type the correct answer in the box. Write the standard form of the quadratic equation modeled by the points shown in the table b
White raven [17]
Y =ax² + bx +c

1) Point (0,7)

7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7

2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------> a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ----> -1=2a + b

4)  a+b= - 3, ----> b= -3 - a (substitute in the second equation)
    2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1, a =2

5) a+b= - 3
    2 + b = -3
b = -5

y=2x² - 5x + 7

8 0
3 years ago
I NEED HELP ASAP <br> question is in picture
Cloud [144]
2x(x-1) has the least common denominator
5 0
3 years ago
What is the measure of o
Helga [31]

Answer:

D

Step-by-step explanation:

We need the formula for arc length (in radians) to solve this problem. The formula is:

s=r \theta

Where

s is the arc length

r is the radius of the circle

\theta is the intercepted angle

In this diagram, we can see that  \theta  is beign intercepted by the big arc with measure 20 cm. So arc length, s, is 20

Also, if we look, we see that the radius is 5 cm, so r = 5

Now, we substitute into formula and find \theta:

s=r\theta\\20=5\theta\\\theta=\frac{20}{5}\\\theta=4

This is given in radians, so \theta is 4 radians

D is the correct answer choice.

6 0
3 years ago
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