Answer: 2a - 7
<u>Step-by-step explanation:</u>
Ana: a
Mrs Vargas: 4a - 4
Leo: 2a + 3
Mrs Vargas - Leo
= (4a - 4) - (2a + 3)
= 4a - 4 -2a - 3
= 2a - 7
<ABC + <ABC = 180
3x- 9 + 7x - 1 = 180
10x - 10 = 180
10x = 190
x = 19
<ABC = 3x- 9 = 3(19) - 9 = 48
Answer:
y = 5
Step-by-step explanation:
WY is the perpendicular bisector of XZ and so divides ΔWXZ into 2 congruent triangles ΔWXY and ΔWZY
Hence WZ = WX ← corresponding sides, thus
5y - 8 = 2y + 7 ( subtract 2y from both sides )
3y - 8 = 7 ( add 8 to both sides )
3y = 15 ( divide both sides by 3 )
y = 5
Answer: c)
.
Step-by-step explanation:
Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

Given function :
Interval : [0,3]
Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that


Since 
then, at x=c, 
From (i) and (ii), we have

Hence, the correct option is c)
.