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Ivan
4 years ago
13

What is the rectangular equivalence to the parametric equations?

Mathematics
1 answer:
Usimov [2.4K]4 years ago
6 0

Answer:

\left(\frac{x-2}{3} \right)^{2}+\left(\frac{y+1}{2} \right)^{2} = 1 (An ellipse)

Step-by-step explanation:

Let consider the following trigonometric identity:

\sin^{2}\theta + \cos^{2}\theta = 1

Each trigonometric function is cleared respectively in given parametric equations:

\cos \theta = \frac{x-2}{3} and \sin \theta = \frac{y + 1}{2}

The equivalent expression in rectangular form is:

\left(\frac{x-2}{3} \right)^{2}+\left(\frac{y+1}{2} \right)^{2} = 1

Which represents an ellipse.

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The fraction of the original mass that was lost in the second month is 1/12.

<h3>What is the fraction?</h3>

A fraction is a non-integer that is made up of numerators and denominators. An example of a fraction is 1/10.

Weight lost in the first month = 1/6 x 120 = 20kg

Weight lost in the second month = 1/10 x (120 - 20)

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Fraction of the original mass that was lost in the second month : weight lost in the second month / total mass

10 kg / 120 = 1/12

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2 years ago
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5 0
3 years ago
If the sphere shown above has a radius of 6 units, then what is the approximate volume of the sphere? A. 1,130.4 cubic units B.
alexandr1967 [171]
Volume of a sphere is calculated with V=(4/3)πr^3
We have the value of r, which is 6.
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5 0
3 years ago
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Answer:

1) sin^{-1}(\frac{1}{\sqrt{2} })=45

2) cos^{-1}(\frac{\sqrt{3} }{2})=30

3) tan^{-1}(\sqrt{3})=60

4) sin^{-1}(1)=90

Step-by-step explanation:

1) Value of sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })

since sin45° = 1/√2

Therefore sin^{-1}(\frac{1}{\sqrt{2} })=45

2).Value of cos^{-1}(\frac{\sqrt{3} }{2})

Since cos 30° = √3/2

Therefore cos^{-1}(\frac{\sqrt{3} }{2})=30

3). Value of tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60

since tan 60° = √3

therefore tan^{-1}(\sqrt{3})=60

4). Value of sin^{-1}(1)

Since sin90°=1

Therefore sin^{-1}(1)=90

3 0
3 years ago
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