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Aloiza [94]
4 years ago
15

Logb sqrt 29/61 Is it logb (29-61)?? am i right

Mathematics
2 answers:
Fiesta28 [93]4 years ago
3 0

Answer:

log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61}})

Step-by-step explanation:

We have been given the expression:

log_b{\sqrt{\frac{29}{61}}

We will use the property:

log_a{\frac{n}{m}}=log_a{m-n}[

Here, a=b,n=\sqrt{29}\text{and}m=\sqrt{61}

So, we will get from the identity:

log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61})

Hence, you are not right because you removed square rrot in final result rest is right.

dlinn [17]4 years ago
3 0
Expand the logarithmic expression. log(base b) sqrt 29/61 

Using the basic log rules:

<span>we get (1/2) [log (base b) 29 - log (base b) 61 ] . 

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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