Answer:
Keisha =$25
Scott =$19
Ryan = $57
Step-by-step explanation:
Let the amount each have be represented by A, B and C
Keisha = A
Scott = B
Ryan = C
Keisha , Scott and Ryan have a total of $101.
That’s
A + B + C = $101
Keisha has $6 more than Scott
A = 6 + B
Ryan has 3 times Scott
C = 3B
Substitute 6+B for A and 3B for C in the first equation.
That’s
A + B + C = 101
6 + B + B + 3B = 101
6 + 5B = 101
Subtract 6 from both sides
6 - 6 + 5B = 101 - 6
5B = 95
Divide both sides by 5
B = 95/5
B = 19
Scott has $19
Recall Keisha has $6 more than Scott B.
That’s A = 6 + B
A = $6 + $19
A = $25
Keisha has $25
Also, Ryan C has 3 times what Scott B has .
That’s
C = 3 x B
C = 3 x 19
C = $57
Therefore, Keisha has $25, Scott has $19 and Ryan has $57
To find the mid segment, it is half of the sum of the bases
for number 13 it's 7+13=20 20/2=10
number 14 it's 12+9=21 21/2=10.5
number 15 it's 22+18=40 40/2=20
Answer:
Step-by-step explanation:
Let <em>P(A) </em>be the probability that goggle of type A is manufactured
<em>P(B) </em>be the probability that goggle of type B is manufactured
<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.
According to the question,
<em>P(A)</em> = 30%
<em>P(B)</em> = 70%
<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.
P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.
will be the probability that a goggle is of type A and is returned within 10 days of its purchase.
will be the probability that a goggle is of type B and is returned within 10 days of its purchase.
If a goggle is returned within 10 days of its purchase, probability that it was of type B:
So, the required probability is 
To subtract? as minus means subract/take away?
