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Tju [1.3M]
3 years ago
14

PLZ HELP I NEED IT ASAP I WILL GIVE BRAINLIST AND POINTS

Mathematics
1 answer:
Alborosie3 years ago
7 0

Answer:

Step-by-step explanation: There are three major forms of linear equations: point-slope form, standard form, and slope-intercept form.

i hole this helps you!

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50 points! Mhanifa please help! I would appreciate it! Random answers will be reported!
alisha [4.7K]

Answer:

x = 4, ∠I = 33°

Step-by-step explanation:

<u>Question 1</u>

Converse to Base Angles Theorem: 28 = 9x - 8,

28 = 9x - 8 (add 8 to both sides)

9x = 36 (divide both sides by 9)

x = 4

<u>Question 2</u>

Since the triangles are congruent, ∠A ≅ ∠G:

∠A = 55 = ∠G

If we consider triangle ALX we have ∠L = 180-55-92 = 33°

And since ∠L ≅ ∠I, ∠I = 33° respectively

4 0
3 years ago
Read 2 more answers
Find the value of x
valina [46]

Answer:

picture is blurry

Step-by-step explanation:

7 0
4 years ago
The number of girls at middle school cyber summer camp was six more than twice the number of boys. There were a total of 156 mid
nordsb [41]
Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106
8 0
4 years ago
A circle with a radius of 10,20 or 4 inches has a central angle of 0.25 radians that intercepts an arc of 25,5 or 16 inches
WARRIOR [948]
The radius would be 10 and the arc would be 5.
I hope this helps.
Have a blessed day!
7 0
3 years ago
Help with the following problem please
Effectus [21]
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle                  = \pi R^2=\pi7^2=49\pi
Area of large shaded circle      = \pi x^2=\pi5^2=25\pi
Area of 4 small shaded circles = 4\pi r^2=4\pi1^2=4\pi
Total area of shaded circles     =25\pi+4\pi=29\pi

Shaded area as a fraction of that of the outer circle 
=\frac{29\pi}{49\pi}=29/49

3 0
3 years ago
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