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andrew-mc [135]

2 years ago

11

Braden has already taken 1 page of notes on his own, and he will take 2 pages during each hour of class. Write an equation that

shows the relationship between the time in class h and the number of pages p.

1 answer:

beks73 [17]2 years ago

7 0

Answer:

2h=2p

1h=1p

Step-by-step explanation:

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Aaron wants to make a path to guide guest through the conservation area.He uses rolls of rope to make the path.He uses 3/4 of a

mel-nik [20]

Answer:

Aaron needs <u>2 more rolls</u> to complete the path.

Step-by-step explanation:

Given:

Total rolls Aaron has = 4

Part of path covered by using $\frac{3}{4}$ of a roll = $\frac{1}{8}$

So, in order to find the number of rolls required to cover the complete path is given using the unitary method.

Rolls used for $\frac{1}{8}$ of a path = $\frac{3}{4}$

Therefore, rolls used to cover the whole path is given by dividing the rolls used for one-eighth of the path and the path covered. This gives,

$=\frac{3}{4}\div \frac{1}{8}$

$=\frac{3}{4}\times \frac{8}{1}$

$=\frac{3\times 8}{4\times 1}$

$=\frac{24}{4}$

$=6\ rolls$

Now, rolls required to complete the path is 6. But Aaron has only 4 rolls.

So, he will need 6 - 4 = 2 rolls more to complete the path.

5 0

3 years ago

Graph the system of equations. then determine wheather the system has no solution, one solution, or infinitely many solutions. I

dimaraw [331]

Answer:

See below in bold.

Step-by-step explanation:

If we add the 2 equations we eliminate x and we get 2y =2.

So y = 1.

Substituting y = 1 in the second equation 1 = x - 3.

So x = 4.

A. One solution: (4, 1).

If we drew a graph we would have 2 lines which intersect at the point (4, 1).

8 0

3 years ago

Read 2 more answers

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago

Fill in the blanks

olga nikolaevna [1]

The answer is
5mn(KUASA DUA) -6gh(KUASA DUA) +2

4 0

2 years ago

BRAINLIEST!!! Can someone tell me how to graph inequalities?

3241004551 [841]

Answer:

whichever way the opening of the sign points go the opposite. if it is less than or equal to, closed circle

Step-by-step explanation:

>

the line would point this way -->

sorry if this doesnt help

8 0

3 years ago

Read 2 more answers