All categories

3 years ago

X+2y=6 2x+4y=12 I need to use substitution to solve, may anybody help?

1 answer:

7 0

$x + 2y = 6$

$x = - 2y + 6$
$2( - 2y + 6) + 4y = 12$
then find y and plug that y value into one of the original equations to find x

Hope this helps!

You might be interested in

Standard Form

erica [24]

$\alpha ) \\ \frac{(8x10^9)}{(2x10^4)} =4x10^5 \\ \\ \alpha ) \\ \frac{(3x10^{12})}{(6x10^9)} = \frac{1}{2}x10^{3} \\ \\ \alpha ) \\ \frac{(7.2x10^9)}{(4.1x10^-4)} = \frac{14}{4.10^{13}} \\ \\ \alpha )) \\ (3.2x10^6)+(4.1x10^8)=>> \\ \\ 
 6.10^6+4.10^8=>> \\ \\ 6000000+100000000==>>10^0$

$\framebox[1.1\width]{Good Luck !} \par
$

8 0

3 years ago

I literally have a test tomorrow and dont know what to do please help

Fittoniya [83]

B is yes and the rest are no. B is the only solution where y equals 1.

3 0

3 years ago

Read 2 more answers

Mrs Smith is completing a mathematics problem. She knows when 6 is added to four times a number, the result is 50. What would be

Lesechka [4]

EXPLANATION:

-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.

data:

-6 that must be added to a number.

-four times a number that is equal to 4x

-a result that is equal to 50

Now with these data we formulate the equation:

$\begin{gathered} \text{Equation:} \\ 6+4x=50;\text{ } \end{gathered}$

if we solve the equation we have:

$\begin{gathered} 6\text{ }+4x=50 \\ 4x=50-6 \\ 4x=44 \\ x=\frac{44}{4} \\ x=-\frac{22}{2} \\ x=\text{ }-11 \end{gathered}$

6 0

1 year ago

Mrs. Zarate is 4 feet 11 inches tall. If there are 2.54 centimeters

shusha [124]

Answer:

149.86 cm

Step-by-step explanation:

4 ft 11 in = 59 inches

2.54(59) = 149.86

5 0

3 years ago

Read 2 more answers

You deposit $2,000 into a bank account that will bay you 4. 8% interest APR ("annual percentage rate") compounded monthly. How m

Nitella [24]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2000\\ r=rate\to 4.8\%\to \frac{4.8}{100}\dotfill &0.048\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &10 \end{cases} \\\\\\ A=2000\left(1+\frac{0.048}{12}\right)^{12\cdot 10}\implies A=2000(1.004)^{120}\implies A\approx 3229.06$

3 0

2 years ago