The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.
In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.
The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

where K is the constant of Coulomb's law.
In this case, you know:
- K= 9×10⁹

- q= 20 uC=20×10⁻⁶ C
- r= 1 m
Replacing in the definition of electric field:

Solving:
<u><em>E=180000 </em></u>
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Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
Learn more:
Answer: 38.2 μC
Explanation: In order to solve this problem we have to use the relationship for a two plate capacitor with a dielectric so:
C= Q/V= we also know that for two paralel plates C=εo*k*A/d and V=E/d
where k is the dielectric constant, A plate area, V is potential difference; E electric field and d the separation between the plates.
reorganizing we have:
Q/A=σ= E*k/εo= 1.2 * 10^6*3.6/8.85 * 10^-12=38.2μC
GEL IT IS COMBINATION OF SOLID AND LIQUID
Answer:
40 miles / hour south
Explanation:
120 miles/3 hours = 40 miles / hour
Answer:
ummm I didn't understand the question