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ivanzaharov [21]
3 years ago
7

A race car driver loses his leg in an accident. Apply Lamarck's and Darwin's theories of evolution to predict whether this disab

ility will be carried forward by his children.
Physics
1 answer:
ASHA 777 [7]3 years ago
7 0
It will not be carried to children ... because genetic defect can be carried to children, not the defect during his lifetime
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6 0
3 years ago
Two common terms for a decrease in velocity are
Colt1911 [192]

deceleration or rėtardation i’m pretty sure (it won’t let me say the second word but it’s correct)

6 0
3 years ago
Read 2 more answers
A hockey puck slides on the ice and eventually stops. How would Newton interpret this behavior?
azamat

That would be a the first law of newton's laws of motion because it stops from an external force

6 0
3 years ago
A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre
Brut [27]

Answer:

The time taken is  t =  0.356 \ s

Explanation:

From the question we are told that

  The length of steel the wire is  l_1  = 31.0 \ m

   The  length of the  copper wire is  l_2  = 17.0 \ m

    The  diameter of the wire is  d =  1.00 \ m  =  1.0 *10^{-3} \ m

     The  tension is  T  =  122 \ N

     

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

              t  =  t_s  +  t_c

Where  t_s is the time taken to transverse the steel wire which is mathematically represented as

         t_s  = l_1 *  [ \sqrt{ \frac{\rho * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_s is the density of steel with a value  \rho_s  =  8920 \ kg/m^3

   So

      t_s  = 31 *  [ \sqrt{ \frac{8920 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_s  = 0.235 \ s

 And

        t_c is the time taken to transverse the copper wire which is mathematically represented as

      t_c  = l_2 *  [ \sqrt{ \frac{\rho_c * \pi *  d^2 }{ 4 *  T} } ]

here  \rho_c is the density of steel with a value  \rho_s  =  7860 \ kg/m^3

 So

      t_c  = 17 *  [ \sqrt{ \frac{7860 * 3.142*  (1*10^{-3})^2 }{ 4 *  122} } ]

      t_c  =0.121

So  

   t  = t_c  + t_s

    t =  0.121 + 0.235

    t =  0.356 \ s

4 0
3 years ago
The load across a 12 v battery consists of a series combination of three resistors 45 ω, 55 ω, and 35 ω. what is the total resis
zubka84 [21]
For n resistors in series, the equivalent resistance is given by the sum of the resistances:
R_{eq} = R_1 + R_2 + ... + R_n

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
R_{eq}=45 \Omega + 55 \Omega + 35 \Omega =135 \Omega
5 0
3 years ago
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