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vlabodo [156]
3 years ago
14

Which prototype is the most cost- and time-effective solution? The Rockets First company needs to hire an engineer to develop a

prototype rocket. The company asks several engineers to provide a cost and time estimate for creating a prototype. Each bid is shown in the table. O Fast Flight Prototype Total Name Cost in Millions Months to Build O Higher Flyers O Orbit or Bust O Infinity & Beyond Fast Flight $400 24 Higher Flyers $500 34 Orbit or Bust $200 10 Infinity & Beyond $900 20 Submit Next Save and Exit Mark this and return​
Chemistry
2 answers:
MArishka [77]3 years ago
4 0

Answer:

Infinity & Beyond

Explanation:

hope I helped!

Alexeev081 [22]3 years ago
3 0

Answer:

Orbit or Bust

Explanation:

Shortest build time and least cost

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What was the eutectic temperature (temperature from the two lines of best fit cross) for the mixture
Ymorist [56]

Answer:

hello your question is incomplete below is the missing part of the question

answer : 104°c

Explanation:

The Eutectic temperature  for the mixture is 104°c

From the chart attached below it can be seen that the temperature from the two lines of best fit cross is 104°c

7 0
3 years ago
Which of the following would be most likely to experience strong intermolecular forces?
ryzh [129]

Answer:

The correct answer is D

Explanation:

Just took quiz

6 0
3 years ago
Use a periodic table to help you answer these questions if needed.
yuradex [85]

Answer:

2 Al and 3 S

Explanation:

Al2S3 so 2 Al and 3 S

3 0
1 year ago
What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

4 0
2 years ago
When 551. mg of a certain molecular compound X are dissolved in 100 g of benzonitrile (CH,CN), the freezing point of the solutio
arsen [322]

Answer:

1.12g/mol

Explanation:

The freezing point depression of a solvent for the addition of a solute follows the equation:

ΔT = Kf*m*i

<em>Where ΔT is change in temperature (Benzonitrile freezing point: -12.82°C; Freezing point solution: 13.4°C)</em>

<em>ΔT = 13.4°C - (-12.82) = 26.22°C</em>

<em>m is molality of the solution</em>

<em>Kf is freezing point depression constant of benzonitrile (5.35°Ckgmol⁻¹)</em>

<em>And i is Van't Hoff factor (1 for all solutes in benzonitrile)</em>

Replacing:

26.22°C = 5.35°Ckgmol⁻¹*m*1

4.90mol/kg = molality of the compound X

As the mass of the solvent is 100g = 0.100kg:

4.9mol/kg * 0.100kg = 0.490moles

There are 0.490 moles of X in 551mg = 0.551g, the molar mass (Ratio of grams and moles) is:

0.551g / 0.490mol

= 1.12g/mol

<em>This result has no sense but is the result by using the freezing point of the solution = 13.4°C. Has more sense a value of -13.4°C.</em>

5 0
2 years ago
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